Answer:
mass Na2SO4 = 14.3816 g
Explanation:
sln Na2SO4:
∴ V = 450 mL
∴ <em>C </em>=<em> </em>0.2250 mol/L
∴ Mw ≡ 142.04 g/mol..... from literature
⇒ mol Na2SO4 = (0.2250 mol/L)(0.450 L) = 0.10125 mol
⇒ mass Na2SO4 = (0.10125 mol)(142.04 g/mol) = 14.3816 g
Answer:
Option B: It remains unused during the reaction
Explanation:
Just took the test and got it right.
No, unless the slime or paper is wet.
Answer is: the temperature is 28.9°C.
n = 2.48; amount of the gas.
V = 30.0 L; volume of the gas.
p = 1559 mmHg ÷ 760 mmHg/atm.
p = 2.05 atm; pressure of the gas.
R = 0.0821 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
T = p·V ÷ (n·R).
T = 302.05 K - 273.15.
T = 28.9°C; temperature of the gas.
If you’re asking if this is true or false, it is false . A HOMOGENEOUS mixture is one the where the substances are evenly distributed and have a uniform composition, while a HETEROGENEOUS mixture is uneven and the substances are part from each like oil and water.