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3 years ago

25. Which units would be the most appropriate to use to measure the degree of attraction between two objects due to their mass?

2 answers:

8 0

The attraction between two objects is force.
As such, if you don't describe the degree of attraction
in units of force, you're doomed.

Whether to use micronewtons, millinewtons, newtons,
giganewtons, ounces, pounds, or tons, really depends on
the size of the force, which in turn depends on the masses
of the two objects and the distance between them. You'll
want to select the unit that produces the most convenient
number. And of course, you'll want to favor the SI units.

Delvig [45]3 years ago

5 0

The correct answer to the question is : Newton ( N )

EXPLANATION:

Before going to answer this question, first we have to understand the gravitational force.

Gravitational force is the mutual force of attraction between two bodies with which every body in the universe is attracted with every other body.

The gravitational force between two bodies having masses M and M' separated by a distance R is calculated as-

Gravitational force F = $G\frac{MM'}{R^2}$

Here, G is known as the universal gravitational force constant.

Hence, gravitational force is a force.

We know that unit of force is newton ( N ).

Hence, the degree of attraction between two objects is measured in newton units.

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You are walking from your math class to your science class. You are carrying books

kolezko [41]

Answer:

1800J

Explanation:

Given parameters:

Weight of the book = 20N

Total distance covered = 45m + 15m + 30m = 90m

Unknown:

Total work performed on the books = ?

Solution:

To solve this problem we must understand that work done is the force applied to move a body through a certain distance.

So;

Work done = Force x distance

Work done = 20 x 90 = 1800J

8 0

3 years ago

The charge per unit length on a long, straight filament is -92.0 μC/m. Find the electric field 10.0 cm above the filament.

Pepsi [2]

Answer:

E = 1.655 x 10⁷ N/C towards the filament

Explanation:

Electric field due to a line charge is given by the expression

E = $[tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}$ [/tex]

where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is

8.85 x 10⁻¹².

Putting the given values in the equation given above

E = $\frac{92\times10^{-6}}{2\times3.14\times8.85\times10^{-12}\times10^{-1}}$

E = 1.655 x 10⁷ N/C

4 0

3 years ago

Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an

vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

q = magnitude of an electronic charge=1.609×10^-19c

B = strength of magnetic field = 5T

d = thickness of sensor = 0.8mm = 0.0008m

By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

0.0015 = I×5/7.446×10^-8

I = (0.0015 × 7.446×10^-8)/5

I = 111.69*10^(-12)

I = 111.69 pA

3 0

3 years ago

1. Calculate the average velocity of the following trip. You walk to Pershing Square 58

Gre4nikov [31]

Explanation:

Velocity = displacement / time

v = √((58 m)² + (135 m)²) / (12 min × 60 s/min)

v = 0.20 m/s

7 0

3 years ago

g a stone with mass m=1.60 kg IS thrown vertically upward into the air with an initial kinetic energy of 470 J. the drag force a

otez555 [7]

Answer:

Height reached will be 28.35 m

Explanation:

Here we can use the work energy theorem to find the maximum height

As we know by work energy theorem

Work done by gravity + work done by friction = change in kinetic energy

$-mgh - F_f h = 0 - \frac{1}{2}mv_i^2$

now we will have

$-1.60(9.8)(h) - 0.900(h) = - 470$

$-16.58 h = -470$

$h = 28.35 m$

so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction

5 0

3 years ago