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Dennis_Churaev [7]
3 years ago
9

What is the total number of electrons possible in the 6s orbital?

Chemistry
1 answer:
mr Goodwill [35]3 years ago
3 0
What is the total number of electrons possible in the 6s orbital? 2
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Describe the atomic theory of atoms
alexandr402 [8]

Answer: Below

                   |

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                   ^

Explanation:

The atomic theory is that all matter is made up of tiny units or particles called atoms. This theory describes the characteristics, structure and behavior of atoms as well as the components that make up atoms. Furthermore, the theory states that all elements are made up of identical atoms.

The atomic theory is a theory in the study of chemistry that states atoms are the building blocks of matter. Atoms contain protons, neutrons and electrons. Protons, which have a positive charge, and neutrons are found in the nucleus of the atom. Electrons, which have a negative charge, orbit the nucleus.

According to the atomic theory, all elements contain atoms. The difference is the number of protons, electrons and neutrons in that atom. For instance, hydrogen contains one proton and one electron but no neutrons. Oxygen, on the other hand contains eight protons, electrons and neutrons. The difference in protons, electrons and neutrons determines the stability and the other properties of any particular element. These elements are grouped according to their atomic masses, which depend on the number of protons and neutrons in each of the atoms. Because oxygen has more protons and neutrons than hydrogen, it has a higher atomic mass.

5 0
3 years ago
Several general characteristics of metabolic reactions or reaction pathways are listed below. sort them into the appropriate met
Kobotan [32]
Answers are:
Catabolism: 
- g<span>enerally exergonic (spontaneous): In this reactions energy is released.
- </span><span>convert NAD+ to NADH. Electrons and protons released in reactions are attached to NAD+.
- </span><span>generation of ATP. ATP is synthesis from ADP.
- </span><span>convert large compounds to smaller compounds. Foe example starch to monosaccaharides.
Anabolism:
</span><span>- convert NADPH to NADP+. Protons and electrons are used to make chemical bonds.
</span>- <span>convert small compounds to larger compounds.</span>
8 0
3 years ago
Read 2 more answers
In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of
Likurg_2 [28]
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

3 0
3 years ago
Read 2 more answers
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans
Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of H_2SO_4 (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H_2SO_4(aq)? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of H_2SO_4(aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_1,M_2\text{ and }V_2  are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL

Putting values in above equation, we get:

2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M

0.044 M is the molarity of H_2SO_4(aq).

4 0
3 years ago
A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin
laila [671]

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

3 0
3 years ago
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