Answer:
A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.
The hot air displacing the cold air is an example of transfer by
Explanation:
Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
Answer:
a) The total force is 4659.8 N
b) The gauge pressure is 50764 Pa
Explanation:
Given:
Pressure inside = 0
Patm = pressure outside = 1.013x10⁵Pa
Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa
a) The area is equal:

The force is:

b) The gauge pressure at the bottom is equal:

Where:
ρ = density = 1000 kg/m³
h = 17 ft = 5.18 m
Replacing:

Speed=0.3*100=30m/s
speed=0.1*50=5m/s
frequency=20/0,5=40HZ
frequency=80/0.2=400HZ
frequency=120/0.4=300HZ
wavelength=340/440=0.77m
wavelength=340/880=0.39m
wavelength=250/400=0.63m
speed=2*50=100m/s
speed=0.5*100=50m/s
The frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
<h3>What is torque?</h3>
Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
Where,
is the frictional torque
is the final angular velocity
is the initial angular velocity
is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
To learn more about the torque, refer to the link;
brainly.com/question/6855614
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