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PSYCHO15rus [73]
4 years ago
9

Please help ASAP. In what direction do you need to apply force to move an object vertically?

Physics
1 answer:
PilotLPTM [1.2K]4 years ago
5 0
The answer is up . tylrhscjwizn
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In the figure calculates the acceleration of the block friction not today
mars1129 [50]

Answer:

A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.

The hot air displacing the cold air is an example of  transfer by

Explanation:

5 0
3 years ago
A car accelerates uniformly from rest at a speed of 1.67 ft s^2 over a distance of 5 yards.What is the acceleration of a car?
Nina [5.8K]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

5 0
3 years ago
Read 2 more answers
A box-shaped metal can has dimensions 6 in by 2 in by 12 in high. All of the air inside the can is removed with a vacuum pump. A
leva [86]

Answer:

a) The total force is 4659.8 N

b) The gauge pressure is 50764 Pa

Explanation:

Given:

Pressure inside = 0

Patm = pressure outside = 1.013x10⁵Pa

Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa

a) The area is equal:

A=12*6=72in^{2} =0.046m^{2}

The force is:

F=delta-P*A=1.013x10^{5} *0.046=4659.8N

b) The gauge pressure at the bottom is equal:

P=\rho gh

Where:

ρ = density = 1000 kg/m³

h = 17 ft = 5.18 m

Replacing:

P=1000*9.8*5.18=50764Pa

8 0
3 years ago
What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?
solong [7]
Speed=0.3*100=30m/s

speed=0.1*50=5m/s

frequency=20/0,5=40HZ

frequency=80/0.2=400HZ

frequency=120/0.4=300HZ

wavelength=340/440=0.77m

wavelength=340/880=0.39m

wavelength=250/400=0.63m

speed=2*50=100m/s

speed=0.5*100=50m/s
7 0
3 years ago
Read 2 more answers
A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane
Nataly [62]

The frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

<h3>What is torque?</h3>

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

Work done by the frictional torque = Change in the rotational kinetic energy of the wheel

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

Where,

\rm T_f is the frictional torque

\rm \omega is the final angular velocity

\rm  \omega_0 is the initial angular velocity

\rm \theta is the angular displacement

Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

To learn more about the torque, refer to the link;

brainly.com/question/6855614

#SPJ1

5 0
2 years ago
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