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Murrr4er [49]
3 years ago
12

What are the characteristics of a proton

Chemistry
2 answers:
Darya [45]3 years ago
6 0

Answer:

found in the nucleus

positive electric charge

Explanation:

apex

Taya2010 [7]3 years ago
4 0

Answer:

A Balanced Atom

Most nuclei also contain neutrons. Perhaps the most essential characteristic of a proton is its positive electrical charge. This charge is equal in magnitude to the negative electrical charge of the electron, which means that the charge of one proton balances out the charge of one electron.

Explanation:

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14. a. Acidic

15. b. Weaker

16. d. Dilute and weak

Explanation:

14. Which type of the solution is one with the pH of 3?

Solution with pH from 1 to 7 are acidic, equal to 7 is neutral and from 7 to 14 basic. The solution with the pH equal to 3 is <u>acidic</u>.

15. The smaller the value of the base dissociation constant (Kb), the <u>weaker</u> the base.

The dissociation reaction of a base (B) is:

B + H₂O → BH⁺ + OH⁻

Kb is defined as:

Kb = ( [BH⁺] × [OH⁻] ) / ( [B] × [H₂O] )

The potency of the base depends on the concentration of the hydroxide ion [OH⁻], so if the Kb ratio is small it means that the concentration of hydroxide ion is smaller so the base will be <u>weaker</u>.

16. A 0.39 M solution of an acid that ionizes only slightly in solution would be termed <u>dilute and weak</u>.

The acid is weak because is only slightly ionizing in solution. The therm diluted is a little bit arbitrarily because we ask yourself "diluted in respect with what"? I would characterize the acid to be diluted at a concentration of 1 M and concentrated at a concentration of 10 M.

Learn more about:

pH

brainly.com/question/1402522

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If the products of a reaction are co2 and 2h2o what is known about the reactants
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What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi
insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

          E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}

                             = 0.535 - 1.065

                             = - 0.53 V

Also, it is known that relation between E^{o}_{cell} and K is as follows.

            E^{o}_{cell} = \frac{RT}{nF} \times ln K

                 ln K = \frac{nFE^{0}_{cell}}{RT}      

Substituting the given values into the above formula as follows.

                 ln K = \frac{nFE^{0}_{cell}}{RT}    

                        =  \frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}  

                ln K = -41.28

                    K = e^{-41.28}    

                        = 1 \times 10^{-18}

Thus, we can conclude that the value of the equilibrium constant for the given reaction is 1 \times 10^{-18}.      

5 0
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