Question

A gas that exerts a pressure of

Answer 1

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

$P_1$ = 15.6 psi

$V_1$ = ???

$P_2$ = 25.43 psi

$V_2$ = 1.895 L

Using Boyle's law:

$P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}$