Example 1: FOREST FIRES
September 24, 2015 - Forest Fire in Indonesia continue to cause smog and haze (Atmosphere) across the region, with air pollutants reaching hazardous levels overnight in Singapore.
The poor air quality shift in wind direction transporting smoke and haze from land and forest (Biosphere) fires in South Sumatra, Indonesia. Their District continues to lead in the number of active fire alerts, with 423 hotspots (Lithosphere) in the last week.
The particulate matter in the air falls out, smothering plants, enriching the soil and thereby moving towards seas, rivers (Hydrosphere) and other water forms that can endangered human's health.
Example 2: DROUGHT
April 8, 2016- Swathes of corn stand withered on the parched rolling hills near the farming town in the Southern Philippines, while shallow cracks scar were once fertile rice paddies. (Biosphere)
El Nino is wreaking havoc in agriculture-rich Cotabato province.
That the villagers are in difficult situation of nothing else to eat. After a lot of incident happened, one of the villagers complained back pain and headache after the rough sleeping of several days.
Unfortunately, he died due to heat stroke of the recent changes in temperature due to Global Warming. (Atmosphere) The animals have nothing to feed the fields are dry making the soil (Geosphere / Lithosphere) less fertile for plants.
The farmers experienced scarce of water (Hydrosphere), crop failures and starving, land drying livestock as well as shortage of potable water.
Control: skunk
Independent: poking (the skunk)
dependent: emission of toxic fumes
Meso−2,3−butanediol is the product of the top reaction
Answer: 5 water molecules
Explanation:
Decomposition of hydrated copper sulphate is given by:
Molar mass of = 159.6 g/mol
According to stoichiometry:
(159.6+18x) g of decomposes to give = 159.6g of
Thus 7.74 g of decomposes to give= g
But it is given 7.74 g of a sample of hydrated salt was found to contain 4.95 g of anhydrous salt.
Thus we can equate the two equations:
x=5
Thus there are 5 water molecules associated with each formula unit.
Answer:
0.166M
Explanation:
In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:
<em>Moles H2SO4:</em>
0.650L * (0.430mol /L) = 0.2795moles H2SO4
<em>Moles KOH:</em>
0.600L * (0.240mol / L) = 0.144 moles KOH
Moles of sulfuric acid that reacts with 0.144 moles of KOH are:
0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.
And remain:
0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.
In 0.650L + 0.600L = 1.25L:
Molar concentration of sulfuric acid:
0.2075 moles of H2SO4 / 1.25L =
<h3>0.166M</h3>