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vlabodo [156]
3 years ago
10

Consider an infinitely thin flat plate of chord c at an angle of attack α in a supersonic flow. The pressure on the upper and lo

wer surfaces are different but constant over each surface; that is, pu(s) = C1 and pl(s) = C2, where C1 and C2 are constants and C2 > C1. Ignoring the shear stress, calculate the location of the center of pressure.

Engineering
1 answer:
amm18123 years ago
4 0

Answer:

X_cp = c/2

Explanation:

We are given;

Chord = c

Angle of attack = α

p u (s) = c 1

​p1(s)=c2,

and c2 > c1

First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.

I've attached the solution

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The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any frictio
Dmitrij [34]

Complete Question

The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass.V = -18 m What is v?X km/h

Answer:

v=23.6m/s

Explanation:

Velocity v_c=18.0km/h

Radius r=21m

initial velocity uu=19=>5.27778

Generally the equation for Angle is mathematically given by

\theta=\frac{v_c}{2r}

\theta=\frac{18}{2*21}

\theta=0.45

\theta=25.7831 \textdegree

Generally

Height of mass

h=\frac{rsin\theta}{\theta}

h=\frac{21sin25.78}{0.45}

h=20.3m

Generally the equation for Work Energy is mathematically given by

0.5mv_0^2+mgh=0.5mv^2

Therefore

v=\sqrt{u^2+2gh}

v=\sqrt{=5.27778^2+2*9.81*20.3}

v=23.6m/s

3 0
3 years ago
Radio Frequency IDentification (RFID) tags and readers are a category of low-end wireless devices that people may not recognize
Fittoniya [83]

Answer:

See explaination.

Explanation:

Radio Frequency Identification (RFID) tags and readers uses the electromagnetic waves to identify and track the attached objects.

A tag is attached to the object which is to be identified or tracked, and reader is used to read the response and send the acknowledgement. Therefore, RFID tags and readers are used in many industries, passports, transportations and pet identification etc.

i.

RFID technology is used in smartcards, implants for pets, passports and library books to identify and track the persons, objects and pets etc.

Hence, we can say that option (i) is true.

ii.

Electronic Product Code (EPC) is a small code stored in the RFID tag. The code stored in the memory is 96 bits which are used to identify the organization which manages the data, unique number to identify the product and a number to identify the particular tag and etc.

EPC is a unique identification number, it can read and be written by the RFID reader. It is used in supply chains instead of a bar code even though expansive.

Hence, option (ii) is true.

iii.

Tags are used to identify and track the objects. It doesn’t belong to base stations and access points as a Wi-Fi networks.

Therefore, option (iii) is false.

iv.

The EPC Generation 2 RFID tag is used to improve the security by enabling the authentication features. It is not the similar way of data transmission in the other wireless situations.

Therefore, option (iv) is false.

Finally, the options (i) and (ii) are TRUE, while (iii) and (iv) are FALSE.

8 0
3 years ago
Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc
madam [21]

Answer:

only if i knew

Explanation:

5 0
3 years ago
java Your program class should be called RomanNumerals Write a program that asks the user to enter a number within the range of
Ann [662]

Answer:

// Scanner class is imported to allow program

// receive input

import java.util.Scanner;

// RomanNumerals class is defined

public class RomanNumerals {

   // main method that signify beginning of program execution

   public static void main(String args[]) {

       // Scanner object scan is created

       // it receive input via keyboard

       Scanner scan = new Scanner(System.in);

       // Prompt is display asking the user to enter number

       System.out.println("Enter your number: ");

       // the user input is stored at numberOfOrder

       int number = scan.nextInt();

     

           // switch statement which takes number as argument

           // the switch statement output the correct roman numeral

           // depending on user input

          switch(number){

           case 1:

               System.out.println("I");

               break;

           case 2:

               System.out.println("II");

               break;

           case 3:

               System.out.println("III");

               break;

           case 4:

               System.out.println("IV");

               break;

           case 5:

               System.out.println("V");

               break;

           case 6:

               System.out.println("VI");

               break;

           case 7:

               System.out.println("VII");

               break;

           case 8:

               System.out.println("VIII");

               break;

           case 9:

               System.out.println("IX");

               break;

           case 10:

               System.out.println("X");

               break;

           // this part is executed if user input is not between 1 to 10

           default:

               System.out.println("Error. Number must be between 1 - 10.");

     }

   }

}

Explanation:

The program is well commented. A sample image of program output is attached.

The switch statement takes the user input (number) as argument as it goes through each case block in the switch statement and match with the corresponding case to output the roman version of that number. If the number is greater 10 or less than 1; the default block is executed and it display an error message telling the user that number must be between 1 - 10.

6 0
3 years ago
Read 2 more answers
“ROUGH
lakkis [162]

The road is in poor condition, slow down.

6 0
3 years ago
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