What happens to the anode in an electrochemical cell

What is the mass in grams of 1.8 mol of Magnesium Sulfide?

Rasek [7]

Answer:

101.466000

Explanation:

N/A

4 0

3 years ago

Determine the acid dissociation constant for a 0.010 M nitrous acid (HNO2) solution that has a pH of 2.70. Nitrous acid is a wea

Soloha48 [4]

Answer:

HNO₂ ⇄ H⁺ + NO₂⁻

Ka = 4.0 × 10⁻⁴

Explanation:

Step 1: Given data

Concentration of nitrous acid (Ca): 0.010 M

pH of the solution: 2.70

Step 2: Write the acid dissociation reaction

Nitrous acid is a weak acid that dissociates according to the following expression.

HNO₂ ⇄ H⁺ + NO₂⁻

Step 3: Calculate the concentration of H⁺

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -2.70 = 2.00 × 10⁻³ M

Step 4: Calculate the acid dissociation constant (Ka)

For a weak acid, we can calculate Ka using the following expression.

Ka = [H⁺]²/Ca

Ka = (2.00 × 10⁻³)²/0.010

Ka = 4.0 × 10⁻⁴

5 0

3 years ago

Can some atoms exceed the limits of the octet rule in bonding? If so, give an example.

harkovskaia [24]

Answer:

Yes. Example: Sulfur hexafluoride (SF₆) molecule

Explanation:

According to the octet rule, elements tend to form chemical bonds in order to have 8 electrons in their valence shell and gain the stable s²p⁶ electronic configuration.

However, this rule is generally followed by main group elements only.

Exception: SF₆ molecule

In this molecule, six fluorine atoms are attached to the central sulfur atom by single covalent bonds.

Each fluorine atom has 8 electrons in their valence shells. Thus, it follows the octet rule.

Whereas, there are 12 electrons around the central sulfur atom in the SF₆ molecule. Therefore, sulfur does not follow the octet rule.

Therefore, the SF₆ molecule is known as a hypervalent molecule or expanded-valence molecule.

6 0

3 years ago

Help me in a quiz this is last Q!

Eduardwww [97]

Answer:

aman tanrım türk müsün

ismin türk ismi

oh my god are you turkish

your name is Turkish name

wooow

6 0

3 years ago

Read 2 more answers

Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have

Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given that:

$Molarity_{NaOH}=5\ M$

$Volume_{NaOH}=?\ L$

$Volume_{HCl}=1\ L$

$Molarity_{HCl}=0.05\ M$

So,

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$0.05\times 1=5\times Volume_{NaOH}$

$Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L$

The volume of NaOH required is - 0.01 L

3 0

4 years ago