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Leokris [45]
3 years ago
9

What happens to the anode in an electrochemical cell

Chemistry
1 answer:
adell [148]3 years ago
3 0
Answer: it loses mass
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g A spontaneous process is one in which: A. releases a large amount of heat B. may happen (is possible) C. will rapidly approach
katrin2010 [14]

Answer:

A. releases a large amount of heat

Explanation:

A reaction is said to be spontaneous if it can proceed on its own without the addition of external energy. A spontaneous reaction is not determined by the length of time, because some spontaneous reactions are completed after a long period of time. They are exothermic in nature. An example is the conversion of graphite to carbon which takes a long period of time to complete. Spontaneous reactions are known to increase entropy in a system. Entropy is the rate of disorder in a system.

In the combustion of fire, energy is released to the surroundings as there is a decrease in energy. This is an example of a spontaneous reaction because it is an exothermic reaction, which causes an increase in entropy and a decrease in energy.

7 0
3 years ago
The pressure of 6.00 L of gas increases from 1.50 atm to 2.00 atm. What is the final volume of the gas, assuming constant temper
xeze [42]

Answer:

first we need to convert everything in SI units

6 0
3 years ago
How much larger are carbon atoms compared to hydrogen atoms?
aleksandrvk [35]

Answer:

Carbon is bigger

Explanation:

There are twice as many number of hydrogen-to-oxygen atoms. This applies to carbon atoms as well when compared to hydrogen atoms.

5 0
2 years ago
What drives this process
m_a_m_a [10]

Answer:

B

Explanation:

cool air never rises so not A

C would mean its getting warmer

and heat flows from warm to cool so not D

we are left with B

if my anwser helps please mark as brainliest.

8 0
3 years ago
Read 2 more answers
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
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