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ryzh [129]
3 years ago
12

Can someone help with these?

Physics
1 answer:
Tcecarenko [31]3 years ago
4 0
<h3>Answer:</h3>

  3.  0.0125 V

  4.  change in time, ∆t

<h3>Explanation:</h3>

3. Faraday's law says ...

\dfrac{\Delta\Phi_B}{\Delta t} \ \text{(through a fixed area) = induced emf}

With suitable units, the magnetic flux Φ is the product of the magnetic field strength and the area of the loop. So ...

  EMF = (∆B/∆t)·A = (0.250 T/s)·(0.05 m²) = 0.0125 V

___

4. Refer to the discussion for problem 3. EMF is proportional to the change of flux with respect to time.

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Answer:

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find the time taken, if the speed of a train increased from 72 km/hr to 90 km/hr for 234 km. leave your answer in seconds
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Answer:

Time taken = 10400 s

Explanation:

Given:

Initial speed of the train, u=72\textrm{ km/h}=72\times \frac{5}{18}=20\textrm{ m/s}

Final speed of the train, v=90\textrm{ km/h}=90\times \frac{5}{18}=25\textrm{ m/s}

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Using Newton's equation of motion,

v - u = at\\a=\frac{v-u}{t}

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v^{2}-u^{2}=2\times \frac{v-u}{t}\times S\\(v+u)(v-u)=\frac{2(v-u)S}{t}\\t=\frac{2(v-u)S}{(v+u)(v-u)}\\t=\frac{2S}{v+u}

Now, plug in 234000 m for S, 25 m/s for v and 20 m/s for u. Solve for t.

t=\frac{2S}{v+u}\\t=\frac{2\times 234000}{25+20}\\t=\frac{468000}{45}=10400\textrm{ s}

Therefore, the time taken by the train is 10400 s.

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