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Mekhanik [1.2K]
3 years ago
13

When an athlete holds a barbell overhead, the reaction force is the weight of the barbell on his hand. how does this force vary

for the case where the barbell is decelerated upward?
Physics
1 answer:
Sonja [21]3 years ago
3 0
The force applied by the competitor is littler than the heaviness of the barbell. At the point when the barbell quickens upward, the power applied by the competitor is more prominent than the heaviness of the barbell. When it decelerates upward, the power applied by the competitor is littler than the heaviness of the barbell.
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EASY BRAINLIEST PLEASE HELP!!
Rudiy27

Answer:

I think the awnser is B (but don't qoute me on that)   if its right then yay but if its wrong im sorry

Explanation:

5 0
3 years ago
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A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 590 m/s . Part A Part complete Wha
Kisachek [45]

Answer:

The recoil velocity is 0.354 m/s.

Explanation:

Given that,

Mass of hunter = 70 kg

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We need to calculate the recoil speed of hunter

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

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Put the value in the equation

0+0=70\times v_{1}+0.042\times590

v_{1}=-\dfrac{0.042\times590}{70}

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8 0
3 years ago
Calculate the average speed in metres per second from Glasgow to Edinburgh
mariarad [96]
This is the same question as the one previously but with more details, so I will just use my previous answer.

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So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)
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