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kaheart [24]
3 years ago
8

Neutral atoms of argon, atomic number 18, have the same number of electrons as each of the following items except: K+ Ca+2 Ne Cl

- S-2
Chemistry
2 answers:
ipn [44]3 years ago
5 0
Neutral atoms of argon, atomic number 18, have the same number of electrons as each of the following items except: Ne

Ne
1s² 2s² 2p⁶

Ar, K(+), Ca(2+), Cl(-), S(2-)
1s² 2s² 2p⁶ 3s² 3p⁶
Vesnalui [34]3 years ago
3 0

Answer : The element that has no same number of electrons as of argon will be, Neon (Ne).

Explanation :

The element is, Argon

The atomic number of argon = 18

The electronic configuration of argon is, 1s^22s^22p^63s^23p^6

The number of electrons in argon = 18

The element is, K^+

The atomic number of K (potassium) = 19

The electronic configuration of 'K' is, 1s^22s^22p^63s^23p^64s^1

The electronic configuration of K^+ is, 1s^22s^22p^63s^23p^6

The number of electrons in K^+ = 18

The element is, Ca^{2+}

The atomic number of Ca (calcium) = 20

The electronic configuration of 'Ca' is, 1s^22s^22p^63s^23p^64s^2

The electronic configuration of Ca^{2+} is, 1s^22s^22p^63s^23p^6

The number of electrons in Ca^+ = 18

The element is, Neon

The atomic number of neon= 10

The electronic configuration of neon is, 1s^22s^22p^6

The number of electrons in neon = 10

The element is, Cl^-

The atomic number of Cl (chlorine) = 17

The electronic configuration of 'Cl' is, 1s^22s^22p^63s^23p^5

The electronic configuration of Cl^- is, 1s^22s^22p^63s^23p^6

The number of electrons in Cl^- = 18

The element is, S^{2-}

The atomic number of S (sulfur) = 16

The electronic configuration of 'S' is, 1s^22s^22p^63s^23p^4

The electronic configuration of S^{2-} is, 1s^22s^22p^63s^23p^6

The number of electrons in S^{2-} = 18

Therefore, the element that has no same number of electrons as of argon will be, Neon (Ne).

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Determine the mass of copper that has the same number of atoms as there are in 6.95 mg of potassium. Answer in units of mg.
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5 0
3 years ago
What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

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brainly.com/question/14090111

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6 0
2 years ago
Two substances are combined and react. After 10 minutes, the chemical reaction has reached equilibrium. Which values would be eq
galina1969 [7]

The extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.

<h3>What is equilibrium?</h3>

Chemical equilibrium refers to the state in which both the reactants and products are present in equal concentrations or amount. In equlibrium, same amount of reactant is converted into product and product into reactant.

So we can conclude that the extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.

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7 0
2 years ago
Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.
vagabundo [1.1K]

Answer:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

Best regards.

8 0
3 years ago
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