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Bingel [31]
2 years ago
8

If the basketball player scored 15 baskets out of 21 tries. How many tries would it take to score 20 baskets?

Mathematics
1 answer:
Evgen [1.6K]2 years ago
6 0
28 tries. The ratio is 5:7, so once you multiply 5 by 4 to get 20, you do the same to 7 to get 28.
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2(4x-3)>-3(3x)+5x help
Roman55 [17]

Answer:

x>1/2

Step-by-step explanation:

2(4x-3)>-3(3x)+5x

Expand the brackets.

8x-6>-9x+5x

Add -9x and 5x

8x-6>-4x

Add 4x and 6x on both sides.

8x+4x>6

Add the like terms.

12x>6

Divide 12 into both sides.

12x/12>6/12

x>1/2

3 0
3 years ago
Read 2 more answers
How do I solve this????
Arlecino [84]
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so       \bf \begin{cases}
a+b=22\\
--------------\\
\boxed{b}=5a+4\qquad thus\\
--------------\\
a+\boxed{5a+4}=22
\end{cases}

solve for "a", to see what the smaller one is

what's "b"?  well, b = 5a + 4
3 0
3 years ago
What is the price of 0.75 m of fabric if the meter costs 31,500
skad [1K]
Look up what is 75% of 31,500
8 0
3 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
What is the answer for #37
denis-greek [22]
They want to make a total of $1200.
55*10=550
55*8=440
440-550=990
1200-990=210
210/35=6
So they should sell the other plants for $6 each.

3 0
3 years ago
Read 2 more answers
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