Answer:
The device acceleration is
a = f/m = f/(w/g)=fg/w
The velocity v is
v= u +at
When u =o
v = at
Substitute the value of a
v = fgt/w
In the case above, It will take more time for a tooth of wheel B and C to make a full turn (slower) than it will for a tooth of wheel A.
<h3>What are gear wheels?</h3>
A gear wheel is known to be a kind of a wheel that is known to be made up of a teeth and/or cogs that is known to function with those of other aspect of the wheel or part.
Note that in the above case, lets use a scenario that Wheel P has 5 teeth. Wheel M has 3 teeth and wheel N has 1 teeth. If wheel P makes a full turn, wheel M turn will be slower as well as wheel N which will take more time.
Therefore, In the case above, It will take more time for a tooth of wheel B and C to make a full turn than it will for a tooth of wheel A.
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The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.
The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.
The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.
The free-body diagram is a graphical representation used to visualize the forces applied to an object.
The equilibrium of forces on the x-axis is:

The equilibrium of forces on the y-axis is:

The equilibrium condition at any point is:

From the free body diagram attached in the second image below,
- the horizontal reaction is located at point A as
- the vertical reaction is located at point A as
- the tension = T
- the weight = W
Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.
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Answer:
Check the explanation
Explanation:
Kindly check the attached image below to get the step by step explanation to the above question.