Answer:
<em>55%</em>
Explanation:
hot reservoir = 1100 K
cold reservoir = 500 K
<em>This is a Carnot system</em>
For a Carnot system, maximum efficicency of the system is given as
Eff = 1 - 
where Tc = temperature of cold reservoir = 500K
Th = temperature of hot reservoir = 1100 K
Eff = 1 - 
Eff = 1 - 0.45 = 0.55 or<em> 55%</em>
This an example solved please follow up with they photo I sent ok
The heat transferred to and the work produced by the steam during this process is 13781.618 kJ/kg
<h3>
How to calcultae the heat?</h3>
The Net Change in Enthalpy will be:
= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg
Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)
= 1/2 x ( 75 + 225) x (5 - 2)
W = 450 KJ
From the First Law of Thermodynamics, Q = U + W
So, Heat Transfer = Change in Internal Energy + Work Done
= 13331.618 + 450
Q = 13781.618 kJ/kg
Learn more about heat on:
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no artical shoul be used here