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2 years ago

What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?

Physics

1 answer:

Alik [6]2 years ago

8 0

Answer:

For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.

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A:10i - 2j -4k and B: i +7j - k. Determine |A-B|

maksim [4K]

A - B = (10i - 2j - 4k) - (i + 7j - k)

A - B = 9i - 9j - 3k

|A - B| = √(9² + (-9)² + (-3)²) = √189 = 3√19

8 0

2 years ago

When a spacecraft travels away from Earth, the gravitational force acting on it

S_A_V [24]

The correct answer is decreases

The further away you are the weaker it would be. That's why at one point you stop being in the field and ti doesn't pull you towards it anymore. Proportionally, if you move towards the Earth then it increases.

6 0

2 years ago

Read 2 more answers

Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr

Sedbober [7]

Answer:

(A) ratio of electric force to weight will be $23.469\times 10^{-10}$

(b) Electric field will be $E=4.26\times 10^{10}N/C$

Explanation:

We have given mass of bee = 100 mg = $m=100\times 10^{-3}=0.1kg$

Charge on bee $q=23pC=23\times 10^{-12}C$

Electric field E = 100 N/C

Weight of the bee $W=mg=0.1\times 9.8=0.98N$

Electric force on the bee $F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N$

So the ratio of electric force on the bee and weight is $=\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}$

(B) To hold the bee in air electric force must be equal to weight of bee

So $mg=qE$

$0.1\times 9.8=23\times 10^{-12}E$

$E=4.26\times 10^{10}N/C$

4 0

2 years ago

Consider the following examples of homeostatic regulation: In response to an increase in plasma K concentrations, secretion of t

TiliK225 [7]

Answer:

Both are examples of negative feedback regulation.

Explanation:

The maintenance of the homeostasis in the body is controlled by the the feedback regulation of the body. Two main types of feedback regulation are positive regulation and negative regulation.

The negative regulation occurs when the final product of the reactions inhibits the further secretion of that product. In the given examples of aldosterone and calcium mechanism, the secretion of aldosterone and calcium decreases as the normal levels are acheived in the body.

Thus, the answer is both are examples of negative feedback regulation.

5 0

2 years ago

Compare and contrast the two different types of mechanical waves?

prohojiy [21]

There are longitudinal and transverse. Both types of mechanical waves require a medium, transport energy, and have defined wavelengths, frequencies, and speeds.
Differences are that transverse waves oscillate along a direction perpendicular to the direction of travel (like shaking a rope up and down). Longitudinal waves like oscillations along a spring and sound waves, oscillate back and forth along the direction of travel.

5 0

3 years ago