The flow of air caused by blend in the blank creates distant blank on earth surface
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Refer to the diagram shown below.
The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.
By definition,
Work = Force x Distance.
(a) The work done by the girl is
W₁ = (17 N)*(3.5 m) = 59.5 J
(b) The work done by the boy is
W₂ = (13 N)*(-3.5 m) = - 45.5 J
(c) The work done by the net force is
W₃ = (4 N)*(3.5 m) = 14 J
Note that W₃ = W₁ + W₂
Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J
The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.
By definition,
Work = Force x Distance.
(a) The work done by the girl is
W₁ = (17 N)*(3.5 m) = 59.5 J
(b) The work done by the boy is
W₂ = (13 N)*(-3.5 m) = - 45.5 J
(c) The work done by the net force is
W₃ = (4 N)*(3.5 m) = 14 J
Note that W₃ = W₁ + W₂
Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J
The area of the plates must have is(A)= 9.91×10⁷ m²
<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>To calculate the the value of a area of the plates of a capacitor, we are using the formula,
C=
Or, A=
Here we are given,
C= The desired capacitance of a capacitor.
= 0.23F
d=distance of separation between the plates.
=3.8mm= 0.0038m.
= permittivity of the vacuum.
=8.854×10⁻¹²F/m
We have to calculate the area of the plates must have = A m².
Now we put the known values in the above equation, we can get
A=
Or, A=
Or, A= 9.91×10⁷ m²
From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²
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