Answer:
The metal atoms in the wire can't move, but their outer electrons can. The force pushes those electrons and they move to further parts of the wire, trying to reach the other end. As the electrons move away, new electrons flow into the wire through the battery to take their place.
Explanation:
Explanation:
F = Gm1m2/r^2
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Complete question:
Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside this metal resistor? If the potential difference due to electric field between the two ends of the resistor is 10 V.
Answer:
The electric field inside this metal resistor is 3125 V/m
Explanation:
Given;
length of the wire, L = 3.2 mm = 3.2 x 10⁻³ m
diameter of the wire, d = 0.4 mm = 0.4 x 10⁻³ m
the potential difference due to electric field between the two ends of the resistor, V = 10 V
The electric field inside this metal resistor is given by;
ΔV = EL
where;
ΔV is change in electric potential
E = ΔV / L
E = 10 / (3.2 x 10⁻³ )
E = 3125 V/m
Therefore, the electric field inside this metal resistor is 3125 V/m
Answer:
Acceleration = 192.3 m/s² (Approx.)
Explanation:
Given:
Force = 125 N
Mass of ball = 0.65 kg
Find:
Acceleration
Computation:
We know that;
Acceleration = Force / Mas
So,
Acceleration = 125 / 0.65
Acceleration = 192.3 m/s² (Approx.)
Answer:
The resolution of an analog-to-digital converter is 24.41 mV
Explanation:
Resolution of an analog-to-digital = (analogue signal input range)/2ⁿ
where;
n is the number or length of bit, and in this question it is given as 12
Also, the analogue signal input range is 100V
Resolution of an analog-to-digital = 100V/2¹²
2¹² = 4096
Resolution of an analog-to-digital = 100V/4096
Resolution of an analog-to-digital = 0.02441 V = 24.41 mV
Therefore, the resolution of an analog-to-digital converter is 24.41 mV
