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3 years ago

A neutral atom has equal numbers of and electrons.

Chemistry

1 answer:

Illusion [34]3 years ago

6 0

True

true

true

true

true

true

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Example of transforming from electric energy to chemical energy<br> please!!!

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Charging a chemical battery is a simple example of converting electricital energy to chemical energy.

Explanation:

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3 years ago

Which statement best describes the relationship between observations and conclusions? A. Observations are based on Conclusions B

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Answer:

B. Conclusions are based on observations

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3 years ago

Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expres

Marizza181 [45]

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

$AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)$

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

$Ksp=[Ag^+][Cl^-]$

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)$

I - 0 0

C - +x +x

E - x x

Which leads to the following modified equilibrium expression:

$Ksp=x^2$

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

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3 years ago

A bottle rocket experiences a 500 N force to the right and 300 N of air resistance to the left. (A) Will accelerate to the left

Tamiku [17]

B) It will accelerate to the right because 500 N> 300 N

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3 years ago

86.14 mL of an acid solution was needed to neutralize 30.24 mL of a base solution of unknown concentrations. A second trial is r

Airida [17]

Answer:

The correct answer is option B.

Explanation:

As given ,that 30.24 mL of base was neutralize by 86.14 mL of acid which means that moles of base present in 30.24 mL are neutralized by moles of acid present in 86.14 mL.

After dilution of base from 30.24 mL to 50.0 mL .Since, the moles of base are same in the solution as that of the moles in solution before dilution. Moles of acid require to neutralize the base after dilution will same as a that of present moles of acid present in 86.14 mL.

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3 years ago