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Dovator [93]
3 years ago
15

The diagram below shows the different phase transitions that occur in matter.

Physics
2 answers:
Margaret [11]3 years ago
7 0

Answer:A

Explanation:matter normally occurs in three phases;solid, liquid and gases. They may change from one phase to another due to temperature difference.

The molecules that makes up solids are held together by bonds. When heat is added,the molecules begin to move as a result,the bonds break and it turns to liquid.this process is called melting. The reverse of melting is freezing.

Liquid are made up of molecules that moves more freely than solids. When heat is added to liquid,the molecules gain more energy and begins to move faster. This causes them to turn to gases.

This process is called evaporation. It occurs at different temperature for different substances.

The particles of gases move more faster and are separated by large distances. A gas can change back to a liquid through condensation.

Luden [163]3 years ago
6 0

Answer:

A. Molecules are speeding up as boiling occurs.

Explanation:

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You would probably have a low frequency due to how much the wavelength is spread out.
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Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
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The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: t=\frac{D_{A}}{v_{B}-v_{A}}

              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

x=x_{0}+vt

where

x_{0} is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is D_{A}.

The equation will be:

x_{A}=D_{A}+v_{A}t

Car B started at the starting line. So, its equation is

x_{B}=v_{B}t

Part A: When they meet, both car are at "the same position":

D_{A}+v_{A}t=v_{B}t

v_{B}t-v_{A}t=D_{A}

t(v_{B}-v_{A})=D_{A}

t=\frac{D_{A}}{v_{B}-v_{A}}

Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

Part B: With the meeting time, we can determine the position they will be:

x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )

x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

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3 years ago
A car sitting at a red light begins to accelerate at 2 m/s2 when the light turns green. It continues with this acceleration unti
jek_recluse [69]

Answer:

    x_total = 600 m

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          v = v₀ + a t

           

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as in this range it has a constant speed

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the total distance traveled is

           x_total = x₁ + x₂

           x_total = 100 + 500

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Answer:

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<span>10 inches
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