Answer:
300000Pa or 3×10^5 Pa
Explanation:
Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.
Using Boyle's law
P1V1 = P2V2
P1 is the initial pressure = 1.5×10^5Pa
V1 is the initial volume = 0.08m3
P2 is the final pressure (required)
V2 is the final volume = 0.04 m3
From the formula, P2 = P1V1/V2
P2 = 1.5×10^5 × 0.08 ÷ 0.04
= 300000Pa or 3×10^5 Pa.
Explanation:
Step one look for the longest chain of carbon atoms
Longest chain is 7 C atoms
Step 2 look for double bonds or others functional groups
it is present in 3rd carbon
Therefore IUPAC name is 3-heptene
From point of stereochemistry it can also be written as trans-3-heptene as the hydrogens are placed in opposite side of the C=C bond.
Hope this helps...
Answer:
0.164541341 g H2
Explanation:
1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).
2g Mg * (1 mol Mg / 24.31 g Mg) = 0.082270671 mol of Mg
2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.
0.082270671 mol of Mg = 0.082270671 mol of H2
3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).
0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2
* Answer can be rounded to your liking *
Answer:
60 grams
Explanation:
We have the balanced equation (without state symbols):
6
H
2
O
+
6
C
O
2
→
C
6
H
12
O
6
+
6
O
2
So, we would need six moles of carbon dioxide to fully produce one mole of glucose.
Here, we got
88
g
of carbon dioxide, and we need to convert it into moles.
Carbon dioxide has a molar mass of
44
g/mol
. So here, there exist
88
g
44
g
/mol
=
2
mol
Since there are two moles of
C
O
2
, we can produce
2
6
⋅
1
=
1
3
moles of glucose
(
C
6
H
12
O
6
)
.
We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.
Glucose has a molar mass of
180.156
g/mol
. So here, the mass of glucose produced is
1
3
mol
⋅
180.156
g
mol
≈
60
g
to the nearest whole number.
So, approximately
60
grams of glucose will be produced.
Answer:
13 kJ
Explanation:
Use the following formula where Q is the Joules needed, m is the mass of the substance, c is the heat capacity, and ΔT is the change in temperature.
Q = mcΔT
The heat capacity of water is 4.186 J/g°C. The mass of water is 234 g. The change in temperature is 13.3°C.
Q = mcΔT
Q = (234 g)(4.186 J/g°C)(13.3°C)
Q = 13,027 J
Since the answer is in Joules, convert to kiloJoules.
13,027 J = 13.027 kJ ≈ 13 kJ
