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mojhsa [17]
3 years ago
11

Tina has been dieting for a total of 13 weeks she lost 3 lb on the first week of her diet but gain the back of pound on the seco

nd week on each remaining week of her diet she lost 2 lb how many pounds has Tina lost in all a. 26 lb B. 22 lb C. 20 lb D. 24 lb
Physics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

D. 24 lb

Explanation:

Tina has been dieting for 13 weeks

First week she lost 3 pounds

Next week she gained 1 pound and did not lose any. This will be subtracted as she has gained a pound

The remaining 11 weeks she lost 2 pounds per week

Weight lost in the 11 weeks = 11×2 =22 pounds

Total weight lost

3-1+22 = 24 lb

Tina has lost 24 pounds in total during the 13 weeks

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Calculate the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol (C3H8O) melts at its melting point
ozzi

Answer:

3.10 mole of C3H8O change in entropy is 89.54 J/K

Explanation:

Given data

mole = 3.10 moles

temperature = -89.5∘C = -89 + 273 = 183.5 K

ΔH∘fus = 5.37 kJ/mol =  5.3 ×10^3 J/mol

to find out

change in entropy

solution

we know change in entropy is ΔH∘fus / melting point

put these value so we get change in entropy that is

change in entropy 5.3 ×10^3 / 183.5

change in entropy is 28.88 J/mol-K

so we say 1 mole of C3H8O change in entropy is 28.88 J/mol-K

and for the  3.10 mole of C3H8O change in entropy is 3.10 ×28.88  J/K

3.10 mole of C3H8O change in entropy is 89.54 J/K

4 0
3 years ago
Read 2 more answers
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
vodka [1.7K]

Answer:

a = 603.59 m/s^2

Explanation:

from the data given . the rate of change in magnetic field is as follow

\frac{dB}{dt} = 280 G/s = 280 \times 10^{-4} T/s

from the faraday's law of induction , the expression for the induced emf in region of radius r as follow

\epsilon = \frac{d \phi}{dt}

\int E.dl = \frac{d(BA)}{dt}

E(2\pi r)= \pi r^2 \frac{dB}{dt}

E = \frac{r}{2} \frac{dB}{dt}

electric field at point P_1 as follow

E = \frac{r}{2} \frac{dB}{dt}

E = \frac{1.5\times 10^{-2}}{2} 280 \times 10^{-4}

E = 6.3\times 10^{-6} V/m

from newton 2nd law of motion, the acceleration of proton is

F = ma

qE = ma

a = \frac{qE}{m}

a = \frac{1.6 \times 10^{-19} (6.3\times 10^{-6})}{1.67\times 10^{-27}}

a = 603.59 m/s^2

5 0
3 years ago
Potential difference is measured in units called
Masja [62]

Answer: Volt

Explanation:

5 0
3 years ago
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I stretch a rubber band and "plunk" it to make it vibrate in its fundamental frequency. I then stretch it to twice its length an
Nikitich [7]

Answer:

The new frequency (F₂ ) will be related to the old frequency by a factor of one (1)

Explanation:

Fundamental frequency = wave velocity/2L

where;

L is the length of the stretched rubber

Wave velocity = \sqrt{\frac{T}{\frac{M}{L}}}

Frequency (F₁) = \frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}

To obtain the new frequency with respect to the old frequency, we consider the conditions stated in the question.

Given:

L₂ =2L₁ = 2L

T₂ = 2T₁ = 2T

(M/L)₂ = 0.5(M/L)₁ = 0.5(M/L)

F₂ = \frac{\sqrt{\frac{2T}{0.5(\frac{M}{L})}}}{4*L} = \frac{\sqrt{4(\frac{T}{\frac{M}{L}}})}{4*L} = \frac{2}{2} [\frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}] = F_1

Therefore, the new frequency (F₂ ) will be related to the old frequency by a factor of one (1).

7 0
3 years ago
A lamp hangs from the ceiling at a height of 2.9 m. If the lamp breaks and falls to the floor, what is its impact speed
ser-zykov [4K]
To solve this there is this website that I found that helps
I am in middle school so I have no idea how to solve this
but
this website may help considering u are in high school and u
(hopefully mind u)
know how to solve this
so to get there u google
"whats impact speed"
and click on the first thing there the website is ehow
8 0
3 years ago
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