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2 years ago

6

Helpppppppp I honestly have no clue

1 answer:

VashaNatasha [74]2 years ago

3 0

North Pole ,land is the answer

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True or False: All cells have different basic chemical composition. *<br> True<br> False

34kurt

True the answer is true lol

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3 years ago

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what is 19.8-17.1

Ostrovityanka [42]

Answer: it should be 2.8

Explanation:

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3 years ago

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Consider the unbalanced equation for the oxidation of aluminum.

SashulF [63]

In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
4Al + 3O₂ → 2Al₂O₃

The coefficients are 4, 3 and 2.

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3 years ago

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Inside an atom, which of these occupies the maximum volume? a) the electrons b) the protons c) the neutrons d) empty space (vacu

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Answer: Electrons

Explanation:The electron itself is small but it takes space as much as an atom by circling around the nucleus.

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3 years ago

The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e

Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

$N_{2}O_{4} \rightarrow 2NO_{2}$

Let us assume that x concentration of $N_{2}O_{4}$ is present at the initial stage. Therefore, according to the ICE table,

$N_{2}O_{4} \rightarrow 2NO_{2}$

Initial : x 0

Change : - 0.1 $2 \times 0.1$

Equilibrium : (x - 0.1) 0.2

Now, expression for $K_{p}$ of this reaction is as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

Putting the given values into the above formula as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

$2 = \frac{(0.2)^{2}}{(x - 0.1)}$

$2 \times (x - 0.1) = (0.2)^{2}$

x = 0.12

This means that $P_{N_{2}O_{4}}$ = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

6 0

3 years ago