Question

How many moles of HCl are needed to completely react with 50.0 mL of 0.250 M NaOH solution? Group of answer choices 1.25 × 10-2 moles 1.25 × 101 moles 2.50 × 10-1 moles

Answer 1

Answer:

$n_{HCl|=1.25\times 10^{-2}\ moles$

Explanation:

We know that , the reaction between NaOH and HCl is given as

$HCL+NaOH\rightarrow NaCl+H_2O$

Form the above reaction we can say that

Number of moles of HCl =Number of moles of NaOH

$n_{HCl} =n_{NaOH}$

Therefore

$n_{HCl}=\frac{0.25\times 50}{1000}\ moles$

$n_{HCl|=12.5\times 10^{-3}\ moles$

$n_{HCl|=1.25\times 10^{-2}\ moles$

Therefore the numbers of moles needed of HCl wil be $1.25\times 10^{-2}\ moles$