Answer: 28.96 V
Explanation:
Given
No of loops on the armature, N = 80
Length of the loop, l = 12 cm = 0.12 m
Width of the loop, b = 8 cm = 0.08 m
Speed of the armature, 1200 rpm
Magnetic field of the loop, B = 0.30 T
To solve this, we use the formula
V(max) = NBAω
Where,
A = area of loop
A = l*b = 0.12 * 0.08
A = 0.0096 m²
ω = 1200 rpm = 1200 * 2π/60 rad/s
ω = (1200 * 2 * 3.142) / 60
ω = 7540.8 / 60
ω = 125.68 rad/s
Substituting the values into the formula
V(max) = NBAω
V(max) = 80 * 0.30 * 0.0096 * 125.68
V(max) = 80 * 0.362
V(max) = 28.96 V
Therefore, the maximum output voltage of the generator would be 28.96 V
