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const2013 [10]
3 years ago
15

Which of the following is the BEST example of statistical evidence?

Engineering
1 answer:
alexandr1967 [171]3 years ago
5 0
Well it would help if there was a picture but wild guess i’m going with B or the second choice.
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Precast double-tee units are generally used as structural floors when:________.
TiliK225 [7]

Answer:

<em>d. floor spans exceed that which is economical with site-cast or hollow-core slabs and exceed 60 feet.</em>

<em></em>

Explanation:

<em> Double tee slabs are prestressed concrete castings usually about 100 m to 150 m long</em>. <em>They are usually used in the construction industry in structures requiring a long floor span (or roof span) exceeding 60 feet in length, that is required to bear additional load (additional load carrying capability</em>). Double tee slabs are usually employed in construction because they shorten construction time. reduce congestion at the construction site, and also reduce construction cost.

<em>They are the required choice in construction when the cost of site casting or hollow-core slabs is no longer economical due to the length of the structure exceeding 60 feet.</em>

8 0
3 years ago
At a festival, spherical balloons with a radius of 140.cm are to be inflated with hot air and released. The air at the festival
Tpy6a [65]

Answer:

find attached

Explanation:

5 0
4 years ago
1. Implement the k-means clustering algorithm either in Java or Python. • The program should be executable with at least 3 param
givi [52]

Answer:

The code for this Question in Python is as follows:

matplotlib inline

from copy import deepcopy

import numpy as np

import pandas as pd

from matplotlib import pyplot as plt

plt.rcParams['figure.figsize'] = (16, 9)

plt.style.use('ggplot')

# Importing the dataset

data = pd.read_csv('xclara.csv')

print(data.shape)

data.head()

# Getting the values and plotting it

f1 = data['V1'].values

f2 = data['V2'].values

X = np.array(list(zip(f1, f2)))

plt.scatter(f1, f2, c='black', s=7)

# Number of clusters

k = 3

# X coordinates of random centroids

C_x = np.random.randint(0, np.max(X)-20, size=k)

# Y coordinates of random centroids

C_y = np.random.randint(0, np.max(X)-20, size=k)

C = np.array(list(zip(C_x, C_y)), dtype=np.float32)

print(C)

# To store the value of centroids when it updates

C_old = np.zeros(C.shape)

# Cluster Lables(0, 1, 2)

clusters = np.zeros(len(X))

# Error func. - Distance between new centroids and old centroids

error = dist(C, C_old, None)

# Loop will run till the error becomes zero

while error != 0:

   # Assigning each value to its closest cluster

   for i in range(len(X)):

       distances = dist(X[i], C)

       cluster = np.argmin(distances)

       clusters[i] = cluster

   # Storing the old centroid values

   C_old = deepcopy(C)

   # Finding the new centroids by taking the average value

   for i in range(k):

       points = [X[j] for j in range(len(X)) if clusters[j] == i]

       C[i] = np.mean(points, axis=0)

   error = dist(C, C_old, None)

# Initializing KMeans

kmeans = KMeans(n_clusters=4)

# Fitting with inputs

kmeans = kmeans.fit(X)

# Predicting the clusters

labels = kmeans.predict(X)

# Getting the cluster centers

C = kmeans.cluster_centers_

fig = plt.figure()

ax = Axes3D(fig)

ax.scatter(X[:, 0], X[:, 1], X[:, 2], c=y)

ax.scatter(C[:, 0], C[:, 1], C[:, 2], marker='*', c='#050505', s=1000)

4 0
4 years ago
A journeyman electrician with 16 years experience on-the-job was removing metal fish tape from a hole at the base of a metal lig
Romashka-Z-Leto [24]

Answer: He should have ensured the following before beginning work;

1) All circuits must be de-energized before beginning work

2) All controls must be deactivated during work. LOTO(Log out tag out) must be practiced irrespective of the experience of the electrian or worker.

3) Technicians and Electrical workers must be instructed to know the unsafe conditions associated with their work.

Explanation:

We cannot assume that because he is experienced he cannot be prone to all this wrong practices. Humans tend to think that with experience people become less prone to errors and study has shown that this is not true. Safety must be a priority.

5 0
3 years ago
the increase of current when 15 V is applied to 10000ohm rheostat which is adjusted to 1000ohm value​
Anastasy [175]
Given data:
•) applied voltage = 15 V
•). Resistance = 1000 ohm

Required:
•). The magnitude of current= ?

•••••••••••••SOLUTION•••••••••••••

We can find the relation ship between current, voltage and resistance with the help of Ohms law.

According to ohms law;

V= IR.

Rearranging the above equation;

I= V/ R

Putt the values in the above equation; we get

I= 15V/ 1000ohm

I = 0.015 A( ampere)

••••••••••••••• CONCLUSION•••••••

The value of the current would be 0.15 ampere when Resistance is equal to 1000 and that of Voltage is equal to 15 V.
4 0
3 years ago
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