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KATRIN_1 [288]
3 years ago
6

Astronauts who landed on the moon during the Apollo 15, 16, and 17 missions brought back a large collection of rocks to the eart

h. The rocks weighed 154 lb when they were on the moon. The acceleration due to gravity on the moon is 5.30 ft/s2.
Engineering
1 answer:
stiks02 [169]3 years ago
8 0

Answer: a) W(earth) = 935.62 lbs

b) Mass of rocks in slugs = 29.06 slugs

Explanation:

a) From Newton's law, W = mg. Whether on the moon or on earth. Although, the mass of the rocks everywhere is the same, that is, mass of rocks on the moon = mass of rocks on earth.

W(moon) = mg(moon)

W(moon) = 154 lbs

g(moon) = 5.30 ft/s2

m = W(moon)/g(moon) = 154/5.3 = 29.06 lb.s2/ft

W(earth) = m g(earth)

g(earth) = 32.2 ft/s2

W(earth) = 29.06 × 32.2 = 935.62 lbs.

b) A slug = 1 lb.s2/ft, therefore the mass of the rocks in slugs is 29.06 slugs.

QED!

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Answer:

b. the supremacy clause

Explanation:

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So in this case where the federal law and the state law do not agree, the feral law has the power to override the law of the state. So oregon has violated the supremacy clause

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You gently place several steel needles on the free surface of the water in a large tank. The needles come in two lengths: some a
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Answer:

attached below

Explanation:

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three balls each have a mass m if a has a speed v just before a direct collision with B determine the speed of C after collision
ratelena [41]

Answer:

Vc2= V(l+e) ^2/4

Vg2= V(l-e^2)/4

Explanation:

Conservation momentum, when ball A strikes Ball B

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Ma(VA)1+ Mg(Vg)2= Ma(Va)2+ Ma(Vg)2

MV + 0= MVg2

Coefficient of restitution =

e= (Vg)2- (Va)2/(Va)1- (Vg)1

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Mg(Vg)2+Mc(Vc)1 = Mg(Vg)3+Mc(Vc)2

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e= (Vc)2 - (Vg)2/(Vg)2- (Vc)1

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Answer & Explanation:

(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 2

= 12 Hz

2fs + fm = 2 * 10 + 2

= 22 Hz

3fs + fm = 3 * 10 + 2

= 32 Hz

4fs + fm = 4 * 10 + 2

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Subtracting:

fs - fm = 10 - 2

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3fs - fm = 3 * 10 - 2

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4fs - fm = 4 * 10 - 2

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5fs - fm = 5 * 10 - 2

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(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 8

= 18 Hz

2fs + fm = 2 * 10 + 8

= 28 Hz

3fs + fm = 3 * 10 + 8

= 38 Hz

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fs - fm = 10 - 8

= 2 Hz

2fs - fm = 2 * 10 - 8

= 12 Hz

3fs - fm = 3 * 10 - 8

= 22 Hz

4fs - fm = 4 * 10 - 8

= 32 Hz

5fs - fm = 5 * 10 - 8

= 42 Hz

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