Answer:
a) 42.08 ft/sec
b) 3366.33 ft³/sec
c) 0.235
d) 18.225 ft
e) 3.80 ft
Explanation:
Given:
b = 80ft
y1 = 1 ft
y2 = 10ft
a) Let's take the formula:
1 + 8f² = (20+1)²
= 8f² = 440
f² = 55
f = 7.416
For velocity of the faster moving flow, we have :
V1 = 42.08 ft/sec
b) the flow rate will be calculated as
Q = VA
VA = V1 * b *y1
= 42.08 * 80 * 1
= 3366.66 ft³/sec
c) The Froude number of the sub-critical flow.
V2.A2 = 3366.66
Where A2 = 80ft * 10ft
Solving for V2, we have:
= 4.208 ft/sec
Froude number, F2 =
F2 = 0.235
d) 
= 18.225ft
e) for critical depth, we use :
![y_c = [\frac{(\frac{3366.66}{80})^2}{32.2}]^1^/^3](https://tex.z-dn.net/?f=%20y_c%20%3D%20%5B%5Cfrac%7B%28%5Cfrac%7B3366.66%7D%7B80%7D%29%5E2%7D%7B32.2%7D%5D%5E1%5E%2F%5E3%20)
= 3.80 ft
15x -/c/ fb is the answer
The application of electro bioengineering uses principles of nick and computer science to design products is application of electrical engineering principles to biology, medicine, conduct, or health.
<h3>What is Bioelectronics?</h3>
- Bioelectronics is the application of electrical engineering principles to biology, medicine, conduct, or health.
- It advances the fundamental concepts, creates knowledge for the molecular to the organ techniques levels, and develops creative devices or methods for the deterrence, diagnosis, and treatment of disease, for patient rehabilitation, and for improving health.
- Bio electromagnetics, instrumentation, neural networks, robotics, and detector technologies are some of the disciplines necessary to develop new knowledge and creations in this area.
- A keystone of this research area is the building of and real-world devices and systems.
- Onsite facilities for prototyping and testing instrumentation systems, fabricating and measuring the performance of implantable devices, and making robotic prostheses, are readily available.
- New detectors and sensor arrays are microfabricated in a 2,000 sq ft cleanroom.
To learn more about Bioelectronics, refer to:
brainly.com/question/21819443
#SPJ4
Answer:
The mass of the air is 0.0243 kg.
Explanation:
Step1
Given:
Stroke of the cylinder is 320 mm.
Bore of the cylinder is 280 mm.
Pressure of the air is 101.3 kpa.
Temperature of the air is 13°C.
Step2
Calculation:
Stroke volume of the cylinder is calculated as follows:
V = 0.0197 m³.
Step3
Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:
PV=mRT
m= 0.0243 kg.
Thus, the mass of the air is 0.0243 kg.
