The Wilson cloud chamber is used to study

A 10,844.0 kg truck is initially at rest. The truck then accelerates across a level road and reaches a constant speed. It takes

lara [203]

Answer:

1,634.1 W

Explanation:

Power = work / time

P = 41,505.4 J / 25.4 s

P = 1,634.1 W

7 0

4 years ago

Which of the following describes the relationship between the area of piston and the force exerted?

kondor19780726 [428]

Answer: Pascal’s principle (apex)

Hope this helps you out!

3 0

3 years ago

Read 2 more answers

Two forces, 80N and 100N acting at an angle of 60 degrees with each other, pull on an object. What single force would replace th

KIM [24]

We use the law of Cosines, resultant force

$F =\sqrt{(F_{1})^2 + (F_{2})^2 + 2 F_{1} F_{2} cos \theta }$

Here, $(F_{1})$ and $(F_{2})$ are forces acting at angle $\theta$ with each other.

Given $F_{1} = 80 N$ , $F_{2} = 100 N$ and $\theta = 60^0$ .

Substituting these given values in above formula we get

$F =\sqrt{(80)^2 + (100)^2 + 2 \times 80 \times 100 \ cos 60^0 } = 156. 20 \ N$ .

Thus, the resultant force is 156 N.

8 0

4 years ago

Suppose you are helping Galileo measure the acceleration due to gravity by dropping a canon ball from the tower of Pisa, You mea

Anni [7]

It is given that the height of the tower is

$h=183 ft.$

The uncertainty the measurement of this height is

$\Delta h=0.2 ft$

Drop time is measured as:

$t=3.5s$

The uncertainty in measurement of time is:

$\Delta t=0.5 s$

Using the equation of motion: $h=ut+\frac{1}{2} at^2$ where, $h$ is the distance covered, $u$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

$u=0$ (because canon ball is in free fall). we need to calculate the value of a=g.

$\Rightarrow h=\frac{1}{2}gt^2$

$\Rightarrow g=\frac{2h}{t^2}\\ \Rightarrow g=\frac{2\times 183ft}{(3.5s)^2}=29.87 ft/s^2$

The uncertainty in this value is given by:

$\Delta g=g\sqrt{(\frac{\Delta h}{h})^2+(\frac{2\Delta t}{t})^2}$

Substitute the values:

$\Delta g=29.87\sqrt{(\frac{0.2 }{183})^2+(\frac{2\times 0.5}{3.5})^2}=29.87\sqrt{1.19\times 10^{-6}+0.08}=29.87\times \sqrt{0.08}=29.87\times 0.28=8.44 ft/s^2$