Hello!
<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
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Formula:

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²
Solving:










Answer:
<span>
C. 5.3s</span>
High school???
No way
It's work.
Answer:
Acceleration = 3m/s^2
Displacement = 126 m
Explanation:
The velocity changed from 12 to 30 m/s in 6 seconds. Using the formula for acceleration we get
(30-12)/6= 18/6= 3m/s^2
Displacement is d=.5a*t^2+v0*t
Inputting acceleration, time, and velocity leaves us with
d=1.5 * 36 + 12 * 6 = 54 + 72 = 126 m
The correct answer is mass
Answer:
The rock has an impact speed of 9.9 m/s.
Explanation:
given information:
object's mass, m = 3 kg
height, h = 5 m
in this case, the potential energy is equal to the kinetic energy
PE = KE
mgh =
mv²
where
m = mass (kg)
g = gravitational constant (9.8 m/s²)
v = velocity (m/s)
so,
mgh =
mv²
gh =
v²
v² = 2gh
v = √2gh
= √(2)(9.8)(5)
= 9.9 m/s