Answer:
Explanation:
From the exercise we know the final x distance, the angle which the projectile is being released and acceleration of gravity
From the equation of x-position we know that
Solving for 
(1)
Now, if we analyze the equation of y-position we got
At the end of the motion y=0
Knowing the equation for in (1)
Solving for t
Now, we can solve (1)
Answer: 56.44°
Explanation:
<u>Given:</u>
- Let u represent the current speed of the plane, <u>1.2 Mach</u>
<em>Converting to SI Units (m/s):</em>
= (1.2 mach)(340 ms^-1 / 1 Mach)
u = 408 m/s
- Speed of sound in air, v = 340 m/s
<u>Find:</u>
- Angle the wave front of the shock wave relative to the plane's direction of motion, θ
We have, sinθ = speed of sound / speed of object
sinθ = v / u
θ = sin^-1 (v / u)
= sin^-1 (340 / 408)
θ = 56.44°
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω
