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3 years ago

The full spectrum of light is what?

Physics

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

Explanation:

"Full-spectrum" is not a technical term when applied to an electrical light bulb. Rather, it implies that the product emulates some important quality of natural light.

Products marketed as "full-spectrum" may produce light throughout the entire visible spectrum, but without producing an even spectral distribution. Some may not differ substantially from lights not marketed as "full-spectrum"

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The diffusion coefficients for species A in metal B are given at two temperatures: T (°C) D (m2/s) 1020 8.01 × 10-17 1290 7.86×

Solnce55 [7]

Explanation:

Below is an attachment containing the solution.

5 0

3 years ago

What are the first three overtones of a bassoon that has a fundamental frequency of 90.0 Hz? It is open at both ends. (The overt

vekshin1

Answer:

$f_{2}=180Hz,f_{3}=270Hz,f_{4}=360Hz\\$

Explanation:

Given data

Frequency f=90 Hz

To find

First three overtones of bassoon

Solution

The fundamental frequency of bassoon is found by substituting n=1 in below equation

f=v/λ=nv/2L

$f_{1}=v/2L$

The first overtone of bassoon is found by substituting n=2

$f_{2}=2v/2L\\f_{2}=2(v/2L)\\as \\f_{1}=v/2L\\So\\f_{2}=2f_{1}\\f_{2}=2(90Hz)\\f_{2}=180Hz$

The second overtone of bassoon is found by substituting n=3

$f_{3}=3v/2L\\f_{3}=3(v/2L)\\as \\f_{1}=v/2L\\So\\f_{3}=3f_{1}\\f_{3}=3(90Hz)\\f_{3}=270Hz$

The third overtone of bassoon is found by substituting n=4

$f_{4}=4v/2L\\f_{4}=4(v/2L)\\as \\f_{1}=v/2L\\So\\f_{4}=4f_{1}\\f_{4}=4(90Hz)\\f_{4}=360Hz$

5 0

3 years ago

A 1.00 x 104 W electric motor is used to lift a

Alexus [3.1K]

Answer: 52%

Explanation:

1W = 1 J/s

motor input is 10000 J/s

Potential energy change

PE = 955(9.81)(25.0) = 234,213.75

power needed to change the PE in that time

P = 234,213.75/ 45 = 5,204.75 Watts

motor is 5204.75 / 10000 = 0.520475 or 52% efficient

4 0

3 years ago

A man pushing a crate of mass

marin [14]

(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.

(b) The net work done on the crate while it is on the rough surface is 23.7 J.

<h3>Magnitude of net force on the crate</h3>

F(net) = F - μFf

F(net) = 280 - 0.351(92 x 9.8)

F(net) = -36.46 N

<h3>Net work done on the crate</h3>

W = F(net) x L

W = -36.46 x 0.65

W = - 23.7 J

<h3>Acceleration of the crate</h3>

a = F(net)/m

a = -36.46/92

a = - 0.396 m/s²

<h3>Speed of the crate</h3>

v² = u² + 2as

v² = 0.845² + 2(-0.396)(0.65)

v² = 0.199

v = √0.199

v = 0.45 m/s

Thus, the magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.

The net work done on the crate while it is on the rough surface is 23.7 J.

The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

7 0

1 year ago

A lightening bolt may carry a current of 11800 A for a short period of time. The permeability of free space is 1.25664 × 10−6 T

Deffense [45]

Answer:

The resulting magnetic field is 5.021 x 10⁻⁵ T

Explanation:

Given;

current in the lightening bolt, I = 11800 A

distance from the bolt, r = 47 m

permeability of free space, μ₀ = 1.25664 × 10⁻⁶ T· m/A

Assume lightening bolt as long straight conductor, then the resulting magnetic field will be calculated as follows;

$B = \frac{\mu_oI}{2 \pi r}$

where;

B is the resulting magnetic field

I is the current in the bolt

r is the distance from the bolt

Substitute the given values and calculate B

$B = \frac{\mu_oI}{2 \pi r} \\\\B = \frac{1.25664 *10^{-6}*11800}{2 \pi (47)} \\\\B = 5.021 *10^{-5} \ T$

Thus, the resulting magnetic field is 5.021 x 10⁻⁵ T

4 0

3 years ago