How many significant digits are in the measurement 589.040 newtons

Physics

2 answers:

dimaraw [331]3 years ago

6 0

Answer:

F = 589.040 N

Number of significant digits = 6

Explanation:

As we know that all the measurements in which the value is given with some decimal then in that case all the numbers in the given measurement is always significant digits.

Since here the force measurement gives the value with decimal as

F = 589.040 N.

So here we can say that total digits in this measurement is significant figures.

So correct answer is 6 digits

Neporo4naja [7]3 years ago

5 0

5... 589. 40....even though the zeros don't really count

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