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stiks02 [169]
3 years ago
14

How many significant digits are in the measurement 589.040 newtons

Physics
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

F = 589.040 N

Number of significant digits = 6

Explanation:

As we know that all the measurements in which the value is given with some decimal then in that case all the numbers in the given measurement is always significant digits.

Since here the force measurement gives the value with decimal as

F = 589.040 N.

So here we can say that total digits in this measurement is significant figures.

So correct answer is 6 digits

Neporo4naja [7]3 years ago
5 0
5... 589. 40....even though the zeros don't really count
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Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

    m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w

Now, we will substitute 0 for both z_{1} and z_{2}, 0 for w, 334.9 kJ/kg for h_{1}, 2726.5 kJ/kg for h_{2}, 5 m/s for V_{1} and 220 m/s for V_{2}.

Putting the given values into the above formula as follows.

     m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w  

     1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0

                q = 6597.711 kJ

Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.

6 0
4 years ago
a boy throws a small stone into a pond. waves spread out from where the stone hits the water and travel to the side of the pond.
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If a piece of wood dropped from a tall building has rezched a velocity of 68.6 m/s , how long has it been falling
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It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s

<u>Explanation:</u>

v = u + at

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t = 68.6 ms^-1 / 9.8 ms^-2

t = 7.0s

It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s

7 0
4 years ago
Small college has 2523 students in 1994 and 2891 students in 1996 if the enrollment follows a linear growth pattern how many stu
alexandr1967 [171]
Since it is specified that the relationship is linear, you could think of a linear graph for this. The base year would be 1994. The first point is at (0,2523) while the second point is (2,2891). The slope would be

m = (2891 - 2523)/(2-0) = 184

The slope-intercept form is y = mx + b. Let's substitute (0,2523) to the equation such that
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4 0
4 years ago
A Carnot engine operates between two heat reservoirs at temperatures THTH and TCTC. An inventor proposes to increase the efficie
Marat540 [252]

Answer:

e_12=1-Tc/Th

This is same as the original Carnot engine.  

Explanation:

For original Carnot engine, its efficiency is given by

e = 1-Tc/Th

For the composite engine, its efficiency is given by

e_12=(W_1+W_2)/Q_H1

where Q_H1 is the heat input to the first engine, W_1 s the work done by the first engine and W_2 is the work done by the second engine.  

But the work done can be written as  

W= Q_H + Q_C with Q_H as the heat input and Q_C as the heat emitted to the cold reservoir. So.  

e_12=(Q_H1+Q_C1+Q_H2+Q_C2)/Q_H1

But Q_H2 = -Q_C1 so the second and third terms in the numerator cancel  

each other.

 e_12=1+Q_C2/Q_H1

but, Q_C2/Q_H2= -T_C/T'

⇒ Q_C2 = -Q_H2(T_C/T')

               = Q_C1(T_C/T')

(T1 is the intermediate temperature)  

But, Q_C1 = -Q_H1(T'/T_H)

so, Q_C2 =  -Q_H1(T'/T_H)(T_C/T') = Q_H1(T_C/T_H) So the efficiency of the composite engine is given by  

e_12=1-Tc/Th

This is same as the original Carnot engine.  

7 0
3 years ago
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