Answer:
Explanation:
The 2 equations we need here are, first:
and then once we solve for the acceleration here:
Δx
Solving for acceleration:
and now we will use that in the other equation:
Δx and
36 = 16 +
Δx and
20 =
Δx and
Δx so
Δx = 50 m
B-Pitcher C-Catcher H-Strike I-Umpire G-Strike Zone E- Foul Ball F- Ball J- Pick-off D-Error A- Shortstop. I think (Sorry for them being out of order. I had to break them down)
We can solve the problem by applying Newton's second law, which states that the resultant of the forces acting on an object is equal to the product between its mass and its acceleration:
![\sum F = ma](https://tex.z-dn.net/?f=%5Csum%20F%20%3D%20ma)
We should consider two different directions: the direction perpendicular to the inclined plane and the direction parallel to it. Let's write the equations of the forces along the two directions, decomposing the weight of the object (mg):
![mg \sin \theta - \mu_K N = ma](https://tex.z-dn.net/?f=mg%20%5Csin%20%5Ctheta%20-%20%5Cmu_K%20N%20%3D%20ma)
(parallel direction) (1)
![mg \cos \theta - N =0](https://tex.z-dn.net/?f=mg%20%5Ccos%20%5Ctheta%20-%20N%20%3D0)
(perpendicular direction) (2)
where
![\theta=35^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D35%5E%7B%5Ccirc%7D)
is the angle of the inclined plane, N is the normal reaction of the plane,
![\mu_K N](https://tex.z-dn.net/?f=%5Cmu_K%20N)
is the frictional force, with
![\mu_K=0.4](https://tex.z-dn.net/?f=%5Cmu_K%3D0.4)
being the coefficient of friction.
From eq.(2), we find
![N=mg \cos \theta](https://tex.z-dn.net/?f=N%3Dmg%20%5Ccos%20%5Ctheta)
and if we substitute into eq.(1), we can find the acceleration of the block:
![mg \sin \theta - \mu_k mg \cos \theta = ma](https://tex.z-dn.net/?f=mg%20%5Csin%20%5Ctheta%20-%20%5Cmu_k%20mg%20%5Ccos%20%5Ctheta%20%3D%20ma)
from which
Answer:
The electric potential (voltage)
produced by a point charge
, at any point in space, is given by the following equation:
Where:
is the Coulomb's constant
is the distance
The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.