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3 years ago

Can yall help me in this pleaseee, i dont get how im supposed to do it..

Chemistry

1 answer:

blagie [28]3 years ago

3 0

It is a triangular shape and there 26 electrons all together but when shared each individual element has 8

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2_PCl3 + __Cl2 → __PCL5 What is the answer

bekas [8.4K]

Answer: 2 PCl3 + 2 Cl2 > 2 PCl5

Explanation: The factors will be 2 moles of PCl3 reacted to 2 moles of chlorine gas Cl2 and the reaction will produce 2 moles of Phosphorous pentachloride PCl5.

For the reactants 2PCl3 +2 Cl2 there will be 2P, Cl (2x3) +

(2x2) so chlorine will have 10. In the product side 2PCl5. 2 P and Cl will have (5x2)=10.

The chemical reaction will have a balance chemical equation.

3 0

3 years ago

Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element?

monitta

Question

Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element?

Answer:

B.) Argon

Hope this helps!

6 0

3 years ago

If a 600 gram radioactive sample goes through 3 half-lives, how would be left?

olga_2 [115]

Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

5 0

3 years ago

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 2.001 g sample of B

Alborosie

Answer: The empirical formula for the given compound is $C_{15}H_{24}O_1$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=5.995g$

Mass of $H_2O=1.963g$

Mass of sample = 2.001 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 5.995 g of carbon dioxide, $\frac{12}{44}\times 5.995=1.635g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.963 g of water, $\frac{2}{18}\times 1.963=0.218g$ of hydrogen will be contained.

Mass of oxygen in the compound = (2.001) - (1.635 + 0.218) = 0.148 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.635g}{12g/mole}=0.136moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.218g}{1g/mole}=0.218moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.148g}{16g/mole}=0.0092moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0092 moles.

For Carbon = $\frac{0.136}{0.0092}=14.78\approx 15$

For Hydrogen = $\frac{0.218}{0.0092}=23.69\approx 24$

For Oxygen = $\frac{0.0092}{0.0092}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 15 : 24 : 1

Hence, the empirical formula for the given compound is $C_{15}H_{24}O_1$

3 0

4 years ago

HELP plz Are beaches made from erosion or deposition?

soldier1979 [14.2K]

Answer:

Desposition

Explanation:

7 0

3 years ago

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Can yall help me in this pleaseee, i dont get how im supposed to do it..​

Can yall help me in this pleaseee, i dont get how im supposed to do it..