Answer:
Explanation:
A )
Th expression for time period for a spring -mass system is as follows
T = 2π
So if mass is doubled , Time period will be √2 or 1.414 times or 5.9 s
B )
If the mass is halved , time period becomes 1 / √2 times or .70 times or 3.0 s
C)
Time period does not depend upon the amplitude of oscillation . So in this case time period will be unchanged ie 4.2 s
D )
As per the formula above , if spring constant k is doubled , time period will be 1 / √2 times or .70 times or 3.0 s
The velocity is 4374.45 m/s.
I got the answer by using v=d/t.
20,000meters / 25min= 4,374.45 m/s.
Answer:
Explanation:
Given
saturated air temperature by 
Dew point temperature is given by 
Dew point is defined as the temperature after which air no longer to uphold the water vapor fuse with it and some water vapor may condense to a liquid.
air continues to rise for 1400 m
i.e. change in temperature would be 
Final temperature 


Answer:
Magnetic field, B = 0.199 T
Explanation:
It is given that,
Radius of circular loop, r = 11.7 cm = 0.117 m
Magnetic flux through the loop, 
The magnetic flux linked through the loop is :


Here, 

or


B = 0.199 T
So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.