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OLEGan [10]
4 years ago
9

13. Adding up all of the

Chemistry
1 answer:
Molodets [167]4 years ago
7 0
Which of the changes are chemical changes
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2CO (g) + O2 (g) → CO2 (g)<br><br> How many grams of O2 are needed to react with 6.64 L of CO2?
allsm [11]

,12.3

Dgrdhc xhyh ghcz dhn tub

8 0
3 years ago
Which element would you expect to be more metallic?<br> (a) Ca or Rb (b) Mg or Ra (c) Br or I
svlad2 [7]

Explanation:

When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.

As calcium (Ca) is a group 2A element and rubidium (Rb) is a group 1A element. Hence, Rb being an alkali metal is more metallic in nature than calcium (alkaline earth metal).

Both magnesium (Mg) and radium (Ra) are group 2A elements. And, when we move down a group then as the size of element increases so, it becomes easy of the metal atom to lose an electron.

As a result, there occurs an increase in metallic character of the element. Hence, Radium (Ra) is more metallic in nature than magnesium (Mg).

Also, both bromine and iodine are group 17 elements. Since, both of them are non-metals and non-metallic character increases on moving down the group.

Therefore, bromine (Br) is more metallic than iodine.

7 0
4 years ago
Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v
Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

Db = Mb/Vb (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: Vb = Vg + Vk (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

Db = (Mg + Mk) / (Vg + Vk)

Db = (Dg * Vg + Dk * Vk)/(Vg + Vk) (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

SG = Substance Density / Reference Density

Therefore:

Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)

SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb * (Vg + Vk) = SGg * Vg + SGk * Vk

SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk

Replacing with the Specific Gravity data, we obtain:

0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk

0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk

0.07 * Vg = 0.05 * Vk

Vg/Vk = 0.05/0.07

Vg/Vk = 0.71

8 0
3 years ago
How is this SI unit of temperature related to the metric unit of Celsius?
shtirl [24]

Answer:

Celsius is currently a derived unit for temperature in the SI system, kelvin being the base unit. ... The two main reference points of the Celsius scale were the freezing point of water (or melting point of ice) being defined as 0 °C and the boiling point of water being 100 °C.

Explanation:

Hope it helps

3 0
3 years ago
How does burning affect an object's property? Burning can cause an object to increase in volume. Burning changes the chemical ma
Jobisdone [24]

Answer: Burning changes the chemical make up of an object.

Explanation:

A chemical change can be defined as a change in the substance when it combines with other kind of substance to form a new substance. A chemical change can also occur when a substance is broken down into two or more products. These changes cannot be reversed. These changes affect the physical make up of an object. For example, burning as when an object is burned it cannot be transformed into its original form. A wood if burned can be converted into ash, water and carbon dioxide cannot regain its original form after burning so burning brings about chemical change in an object.

3 0
3 years ago
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