Answer:
I dont know your question
Explanation:
can you tell me more about your question then I could help!
<span>a)
</span>First order
in A and zero order in B
<span>ln [A]
= (ln 0.1) (2) + ln Ao = ln 0.01 + ln Ao = ln 0.01 Ao = 1.0% of A will remain</span>
<span>b)
</span>First
order in A and first order in B
<span>1/[A] – 1/[A]0= kt where t+=1 and k=9</span>
[A]/[A]=1/19=0.053=5.3%
<span>c)
</span>Zero
order in both A and B
<span>[A]0-[A] = kt</span>
Then at 2
hours [A]=0 All of it has reacted.
<span> </span>
The moles of fluorine present are 71/19 = 3.74
Now, we know that one mole of gas at 273 K and 101.3 kPa (S.T.P.) occupies 22.4 liters
Volume of 3.74 moles at S.T.P = 3.74 x 22.4
Volume = 83.776 L = 83,776 mL
Now, we use Boyle's law, that for a given amount of gas,
PV = constant
P x 6843 = 101.3 x 83776
P = 1,240 kPa
Lithium is in the first column of the periodic table and thus can only form one bond with another atom (its ion is Li+)
Oxygen can form two bonds (as in the dioxygen O2).
Hence if you conbine Li and O it has to be Li2O.
Answer : 
Explanation : In the molecule of the hydrogen bonding forces tend to resist any phase transition form liquid state to gaseous phase, and these hydrogen bonding forces are greater usually when the hydrogen is bound to an electronegative atom like chlorine, fluorine,oxygen,etc. This then lowers the viscosity of the compound.
