Answer:
Explanation:
Variation problems involve fairly simple relationships or formulas, involving one variable being equal to one term. Here follows the most common kinds of variation.
The constant of variation in a direct variation is the constant (unchanged) ratio of two variable quantities. In the following equation y varies directly with x, and k is called the constant of variation:
y=kx
Another form of variation is the inverse variation which works when there is a relationship between two variables in which the product is a constant. When one variable increases the other decreases in proportion so that the product is unchanged.
We can find out how acidic or basic a substance is by using the pH scale. The greater the pH number is, the more basic the substance is. In order to convert from pOH to pH, we can use the equation pH = 14 - pOH. Our new pH values are then solution A = 12.5, solution B = 7.0, and solution C = 0.5. The answer is then solution A, because it has the greatest pH value.
Hope this helps!
Answer:
4.
Explanation:
I believe that #4 best shows the runoff in the system. We see 2/3 which is precipertation falling and 4 shows this water running off the mountains into the ocean.
Answer: 8.95 hours
Explanation:
Coloumb of electricity deposits 1 mole of Nickel
1 mole of Nickel weighs = 58.7 g
Given quantity = 1.0 kg = 1000 g (1kg=1000g)
58.7 g of Nickel is deposited by 193000 C of electricity
1000 g of Nickel is deposited by = of electricity
where Q= quantity of electricity in coloumbs = 3287904.6C
I = current in amperes = 102 A
t= time in seconds = ?
(1h=3600 sec)
Thus 8.95 hours it takes to plate out 1.0 kg Ni from aqueous solution, if the electrical current is 102 A.
Answer:
8 water molecules
Explanation:
The hydrogen bond may be H-O~H-N or H-N~H-O; in the first one, the hydrogen bond is between an oxygen atom and a hydrogen which is covalently bonded to a nitrogen atom. The second one is the hydrogen bond of a nitrogen atom with a hydrogen covalently bonded to a oxygen one. The first case would be the hydrogen bonds that water may form with the hydrogen of the urea; the second ones would be the hydrogen bonds that urea may form with water molecules. So, for each nitrogen in urea there would be a hydrogen bond, and for each hydrogen too. Finally, the oxygen in the urea molecule may form hydrogen bonds with water as well, but it has two lone pairs to donate, so the oxygen atom may form hydrogen bond with 2 water molecules:
N=(2 because of the oxygen atom of the urea)+(4 because of the hydrogen bonded to nitrogen)+2(because of the nitrogens).
N=8.