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Basile [38]
3 years ago
12

The molecular mass of the compound is 90 amu. What is the molecular formula for C2H5O?

Chemistry
2 answers:
ANEK [815]3 years ago
8 0

First let us get the molecular mass of the compound C2H5O.

C has molar mass of 12 amu, H is 1 amu, while O is 16 amu, therefore:

C2H5O = 12 amu * 2 + 1 amu * 5 + 16 amu = 45 amu

So to get 90 amu, simply double all the elements, therefore:

 

<span>C4H10O2</span>

Wewaii [24]3 years ago
6 0

Let us assume that the given formula of elements is empirical formula where elements have simplest whole number ratio

The empirical mass =  2 X atomic mass of carbon + 5 X atomic mass of hydrogen + at mass of O

The empirical mass = 2 X 12 + 5 + 16 = 45

The ratio of molecular mass and empirical mass = 90 / 45 = 2

Molecular formula is obtained by multiplying the empirical formula with this ratio / factor

molecular formula = 2 X (C2H5O) = C4H10O2

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It will be halve of T

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6 0
3 years ago
Explain why the electron configuration of 2-3-1 represents an atom in an excited state?
baherus [9]

Answer:

See explanation

Explanation:

If we look at the electron configuration closely, we will discover that the element must have had a ground state electron configuration of 2,4.

This is because, the innermost shell usually holds two electrons while the outer shells hold eight electrons each. The four electrons must be accommodated in the second shell in the ground state configuration of the compound.

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6 0
2 years ago
Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) =&gt; CH 3OH(l) Using the following information: C(graphite) +
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Answer:

\Delta H for the given reaction is -238.7 kJ

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CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)  \Delta H_{3}= 726.4 kJ

---------------------------------------------------------------------------------------------------

C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ

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3 0
3 years ago
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