The answer is option a.soft and easy to cut
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Answer:
The answer to this is
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Explanation:
To solve this we first list out the variables thus
Density of the water = 1.00 g/mL =1000 kg/m³
density of mercury = 13.6 g/mL = 13600 kg/m³
Standard atmospheric pressure = 760 mmHg or 101.325 kilopascals
Therefore from the equation for denstity we have
Density = mass/volume
Pressure = Force/Area and for a column of water, pressure = Density × gravity×height
Therefore where standard atmospheric pressure = 760 mmHg we have for Standard tmospheric pressure= 13600 kg/m³ × 9.81 m/s² × 0.76 m = 101396.16 Pa
This value of pressure should be supported by the column of water as follows
Pressure = 101396.16 Pa = kg/m³×9.81 m/s² ×h
∴
= 10.336 meters
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Answer:
<em>Option 'D' is correct.</em>
Step-by-step explanation:
Since we have given that
We will first find the "Discrimination":
Since discriminant is less than 0 i.e. D<0.
So, there will no real roots.
Hence, D = -28 and there is no real roots.
Therefore, Option 'D' is correct.
Explanation:
Answer:
- covalent bond
- polar covalent bond
- ionic bond
- metallic bond
Explanation:
<h2>hope it helps you </h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>Thank uu</h2>
Answer:
1. a = 2, b = 1 and c = 2
2. a = 1, b = 3, c = 2 and d = 2
Explanation:
According to law of conservation of mass, the mass can neither be created nor destroyed.
Hence, for a chemical equation the left hand side should be equal to the right hand side.
Therefore, the two balanced equations are;
2 CO + O₂ → 2 CO₂
C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O