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Gennadij [26K]
3 years ago
15

When making sweet tea, McDonalds adds the sugar while the tea is hot. The sugar is added at this step so that the tea can be as

sweet as possible. What type of solution is this?
A. unsaturated
B. saturated
C. supersaturated
D. saturated then supersaturated when it cools
Physics
2 answers:
Naya [18.7K]3 years ago
4 0

Answer:

its D . good luck i hope this helps and please thank and name the brainly

Explanation:

Lilit [14]3 years ago
3 0

Answer:

d

Explanation:

we need the tea to be at first moist in order to get much more flavor. then supersaturated so that it increases the concentration of the flavor by it not being too sweet nor too salty. so just right.

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Atoms with electronegativity differences below 0.4 generally form covalent<br>bonds. True or False​
STALIN [3.7K]

Answer:

True

Explanation:

Electronegativity difference of less than 0.4 characterized covalent bonds. For two atoms with an electronegativity difference of between 0.4 and 2.0, a polar covalent bond is formed-one that is neither ionic nor totally covalent.

7 0
3 years ago
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The hydrocarbon C2H4 is a member of the_series.
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Answer:

alkene series

Explanation:

the alkene series are the hydrocarbons e.gc2h4 c3h8

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3 years ago
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Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment
Drupady [299]

Answer:

u_K=0.862

Explanation:

The force of friction between the quails feet and the ground is:

F=m*a

F_K=m*a

F_K=u_k*m*g

u_K*m*g=m*a_c

u_K*g=a

u_K=\frac{a_c}{g}

a_c=\frac{v^2}{r}

So the coefficient of static is solve

u_K=\frac{\frac{v^2}{r}}{g}

u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}

u_K=0.862

4 0
3 years ago
A child is sliding down a slide at the playgound. is mechanicalenergy conserved
Flauer [41]

No. Mechanical energy is not conserved.  There's quite a bit of friction on the slide.  So some of the potential energy is lost to heat on the way down, and the child arrives at the bottom with hot pants and less kinetic energy than you might expect.

5 0
3 years ago
According to the intuitive guess you just made, is the overall momentum of the two-cart system after the collision greater than,
Aloiza [94]

Answer:

It is equal to the overall momentum before collision, so far no external object is involved.

Explanation:

Momentum is always conserved during collision as a rule. This is equal to the product of the mass and velocity. Thank you.

5 0
3 years ago
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