Answer:
Do find the answer in the attachment herein.
Explanation:
From the attached diagram:
I. Activation energy = Activated complex - ∆H(reactants)
Activation energy = 162-140 = 22Kj.
II. ∆H(reaction) = ∆H(products) - ∆H(reactants)
∆H(reaction) = 37 - 140 = -103Kj.
Answer: The weight of the air displaced by the balloon is less than the volume of the balloon.
Explanation:
A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner heats the liquid propane to a gaseous state to generate a huge flame, which can reach more than 3 meters, thus heating the air mass inside the balloon. In this way,<u> its density is modified with respect to the air that surrounds it</u>, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.
Now, if we know that the density of a body is directly proportional to its mass
and inversely proportional to its volume
:
We can deduce that <u>by increasing the volume of the body, its density will decrease.</u>
This is proof of <em><u>Archimedes' Principle</u></em>:
<em>A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.</em>
In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.
Answer:
E = 24000 N/C = 24 KN/C
Explanation:
The electric field experienced by a test charge is given by the following formula:
where,
E = Electric Field = ?
F = Force of attraction = 3 x 10⁻⁶ N
q = Charge on piece of lint = 1.25 x 10⁻¹⁰ C
Therefore, using these values in the equation, we get:
<u>E = 24000 N/C = 24 KN/C</u>
The concept to develop this problem is the Law of Malus. Which describes what happens with the light intensity once it passes through a polarized material.
Mathematically this can be expressed as
Where
I = New intensity after pass through the Polarizer
= Original intensity
= Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.
When the light passes perpendicularly through the first polarizer, the light intensity is reduced by half which will cause the intensity to be at the output of the new polarizer, mathematically:
Solving to find the angle we have
The orientation angle of the second polarizer relative to the first one is 43.11°