Let the velocity of the vehicle be
V₁ = (21, 0)
Let the velocity of a raindrop be
V₂ = (a, b)
When returning, the raindrop is vertical.
Therefore a = 21 m/s
When driving north, a raindrop makes an angle of 36° with the vertical, therefore
tan(36°) = a/b = 21/b
b = 21/tan(36°) = 28.9 m/s
The speed of a raindrop is
√(a² + b²) = √(441 + 835.44) = 35.73 m/s
The angle is 90-36 = 54° with the ground.
Answer: 35.7 m/s at 54° relative to the ground.
Answer:
Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature. If a specimen increases in length from l1 to l2 when its temperature is raised θ°, then the expansivity (α) is given by: l2 = l1(1 + αθ). This relationship assumes that α is independent of temperature. This is not, in general, the case and a more accurate relationship is: l2 = l1(1 + aθ + bθ2 + cθ3…), where a, b, and c are constants.
l2 = l1(1 + αθ).
l2 = l1(1 + aθ + bθ2 + cθ3…),
Known data:
time=4,2s
Earth's acceleration:9.8m/s²
Formulas needed:
t=v÷g
S=vt+(gt²)÷2
Solution:
t=v÷g
4,2=v÷9,8
v=9,8×4,2
v=41,16m/s
S=vt+(gt²)÷2
S=41,16×4,2-9.8×(4,2)²÷2
S=86.436m