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3 years ago

Consider the following reaction:

Chemistry

1 answer:

vfiekz [6]3 years ago

3 0

Answer:

Kc = 4.76

Explanation:

To find the concentrations of CO and H₂ at equilibrium, you have to set up an ICE (Initial, Change, Equilibrium) table.

CO (g) + 2H₂(g) ⇌ CH₃OH (g)

I 0.32 M 0.53 M 0

C -x -2x +x

E 0.32-x 0.53-2x 0.16 M

Since you know the concentration of CH₃OH at equilibrium, it would be equal to x since 0 + x = 0.16. So,

[CH₃OH] = 0.16 M

[CO] = 0.32 - 0. 16 = 0.16 M

[H₂] = 0.53 - 2(0.16) = 0.21 M

Now that you have all the concentrations at equilibrium, you can calculate the equilibrium constant.

Kc = products ÷ reactants

= [CH₃OH] ÷ [CO][H₂]²

= 0.16 ÷ (0.16)(0.21)

Kc = 4.76

The equilibrium constant at this temperature is 4.76.

Hope this helps.

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