Question

How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following reaction?
4Li + O2 → 2Li2O (My answer: C)


1

2

4

8

Answer 1

4Li + O₂ = 2Li₂O

Li : Li₂O = 4 : 2 = 2 : 1

2 : 1
x : 4

x=4*2/1=8 mol

D) 8

Answer 2

Answer: The correct answer is 8.

Explanation: For the following equation:

$4Li(s)+O_2(g)\rightarrow 2Li_2O(s)$

As oxygen gas is in excess, so lithium metal is considered as the limiting reagent because it limits the formation of product.

By Stoichiometry,

2 moles of lithium oxide is produced by 4 moles of Lithium

So, 4 moles of lithium oxide will be produced by = $\frac{4}{2}{\times 4$ = 8 moles of lithium metal.

So, the correct answer is 8.