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-Dominant- [34]
2 years ago
15

How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following

reaction?
4Li + O2 → 2Li2O (My answer: C)


1

2

4

8
Chemistry
2 answers:
Oduvanchick [21]2 years ago
6 0
4Li + O₂ = 2Li₂O

Li : Li₂O = 4 : 2 = 2 : 1

2 : 1
x : 4

x=4*2/1=8 mol

D) 8
meriva2 years ago
6 0

Answer: The correct answer is 8.

Explanation: For the following equation:

4Li(s)+O_2(g)\rightarrow 2Li_2O(s)

As oxygen gas is in excess, so lithium metal is considered as the limiting reagent because it limits the formation of product.

By Stoichiometry,

2 moles of lithium oxide is produced by 4 moles of Lithium

So, 4 moles of lithium oxide will be produced by = \frac{4}{2}{\times 4 = 8 moles of lithium metal.

So, the correct answer is 8.

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Identify the group of elements that corresponds to each of the following generalized electron configurations and indicate the nu
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(b) [noble gas] ns² (n-1)d²: Number of unpaired electron is 2 and belongs to group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹: Number of unpaired electron is 1 and belongs to group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶ : Number of unpaired electron is 6 and belongs to group 8 of the periodic table.

Explanation:

In the Periodic table, the chemical elements are arranged in 7 rows, called periods and 18 columns, called groups. They are organized in increasing order of atomic numbers.

(a) [Noble gas] ns² np⁵

As the total number of electrons in the p-orbital is 5. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 5 electrons in np orbital. <u>So there are 7 valence electrons.</u>

Therefore, this element belongs to the group 17 i.e. halogen group of the periodic table.

(b) [noble gas] ns² (n-1)d²

As the total number of electrons in the d-orbital is 2. Therefore, the number of unpaired electrons is 2.

This element has 2 electrons in ns orbital and 2 electrons in (n-1)d orbital. So there are <u>4 valence electrons.</u>

Therefore, this element belongs to the group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹

As the total number of electrons in the p-orbital is 1. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 1 electron in np orbital. So there are <u>3 valence electrons</u>.

Therefore, this element belongs to the group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶

As the total number of electrons in the f-orbital is 6. Therefore, the number of unpaired electron is 6.

This element has 2 electrons in ns orbital and 6 electrons in (n-2)f orbital. So there are <u>8 valence electrons.</u>

Therefore, this element belongs to the group 8 of the periodic table.

3 0
2 years ago
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