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3 years ago

_____ is the measure of the degree of charge separation within a polar molecule.

Chemistry

2 answers:

yawa3891 [41]3 years ago

7 0

Your answer is .....

The dipole Moment

Good luck! :)

mr_godi [17]3 years ago

3 0

Answer : Dipole moment is the measure of the degree of charge separation within a polar molecule.

Explanation :

Dipole moment : It is a quantity which describes that the two opposite charges are separated by the distance. Or it is defined as the product of magnitude of the separated charges and distance between the two charges in a polar molecule.

The formula used for Dipole moment is,

$\mu=q\times d$

where,

$\mu$ = Dipole moment

q = separated charge

d = distance between the two charge

Hence, dipole moment is the measure of the degree of charge separation within a polar molecule.

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a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the

butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

$\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}$

Given ,

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7 ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (21.7 + 273.15) K = 294.85 K

T₂ = (28.1 + 273.15) K = 301.25 K

Using above equation as:

$\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}$

$\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K }}{0.998\ atm}$

$n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol$

Solving for n₂ , we get:

n₂ = 0.39 mol

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