Concentration of H+ ions in HNO3 solution is 10⁻¹ which is equal to 0.1 M
![\bf \: pH \: = - log[{h}^{ + }]](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5C%3A%20pH%20%5C%3A%20%20%3D%20%20-%20log%5B%7Bh%7D%5E%7B%20%2B%20%7D%5D)
putting the value we get
![\sf \dashrightarrow \: pH \: = - log \: [ \frac{1}{10}] \\ \\ \sf \dashrightarrow \: pH \: = - log \: {10}^{ - 1} \\ \\ \sf \dashrightarrow \: pH \: = 1](https://tex.z-dn.net/?f=%20%20%5Csf%20%5Cdashrightarrow%20%20%5C%3A%20pH%20%5C%3A%20%20%3D%20%20-%20log%20%5C%3A%20%5B%20%5Cfrac%7B1%7D%7B10%7D%5D%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20%20%5C%3A%20pH%20%5C%3A%20%3D%20%20%20-%20log%20%5C%3A%20%7B10%7D%5E%7B%20-%201%7D%20%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20%20%5C%3A%20pH%20%5C%3A%20%3D%201)
So, the required option is A) 1
The molecular mass of sucrose is 342.3<span> grams per mole (g/mol).</span>
I would go with B. Not everyone can learn this skill.
Answer:
Redox type
Explanation:
The reaction is:
2Cr + 3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃
2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.
If we see oxidation state, we see that chromium changes from 0 to +3
Iron changed the oxidation state from +2 to 0
Remember that elements at ground state has 0, as oxidation state.
Iron is being reduced while chromium is oxidized. Then, the half reactions are:
Fe²⁺ + 2e⁻ ⇄ Fe (Reduction)
Cr ⇄ Cr³⁺ + 3e⁻ (Oxidation)
When an element is being reduced, while another is being oxidized, we are in prescence of a redox reaction.
