Answer:
b. Beta emission, beta emission
Explanation:
A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).
Now let us look at the N/P ratio of each atom;
For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6
For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4
For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.
For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.
Is there any answer choices before i get started on working out the problem
Kr= krypton
K= potassium
C=carbon
En= neon
Si= silicon
Au= gold
Ni= nitrogen
Br= berillium
Mg=magnesium
Mn= mangenese
Al: aluminum
Answer:
1 in. =2.54 cm
3*(10^-4)*2.54=7.62*10^-4
Explanation:
Cross breeding plants to make better apples
