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SCORPION-xisa [38]

3 years ago

13

Give an example of one technology that is well matched to the needs of the environment, and one technology that is not.

2 answers:

omeli [17]3 years ago

8 0

Answer:

the internet is a need everywhere to do work and games systems is a technology that is just a want.

Explanation:

asambeis [7]3 years ago

6 0

When you say technology do u mean any type of just like phone?

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A ballistic pendulum consists of a 3.60 kg wooden block on the end of a long string. From the pivot point to the center‐of‐mass

Pavel [41]

Answer:

17.799°

Explanation:

When the bullet hits the block at that time the momentum is conserved

So, initial momentum = final momentum

$P_i=P_f$

So $28\times 10^{-3}\times 210=(3.6+0.028)v_f$

$v_f=1.6207\ m/sec$

Now energy is also conserved

So $\frac{1}{2}\times (3.6+0.028)\times 1.6207^2=(3.6+0.028)\times 9.81\times 2.8(1-cos\Theta )$

$cos\Theta =0.8521So\ \Theta =17.799^{\circ}$

3 0

3 years ago

Select the correct answer.<br> Which equation gives you the amount of work performed?

Fantom [35]

Answer:

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this is the answer

5 0

4 years ago

Birdie Par owns a company that makes golf gloves. She is thinking about introducing a new glove, which would require an addition

melamori03 [73]

Birdie's company will make a profit of $30,000 if she sells 3,000 gloves at the $15 price.

Step-by-step Solution:

Break even point= fixed cost/ selling price - variable cost

here the fixed cost is= $20,000

selling price= $15 and variable cost = $5

BEP= 20,000/ 15-5= 20,000/10= 2000 units

b. if they sell 3000 gloves, the contribution profit will be

total revenue= 3000*$15= $45,000

contribution= selling price- variable cost, 15-5= $10 per unit

the profit is= 3000*$10= $30,000

What is variable cost?

A variable cost is one that varies in relation to either the volume of production or the number of services provided. There should be no variable costs if no production or services are provided. Variable costs should rise in tandem with increases in production or services.

To learn more about Profit Calculation, visit: brainly.com/question/28177180

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3 0

2 years ago

He is going ___ in the hot air ballon

Vladimir [108]

no artical shoul be used here

5 0

3 years ago

Initially when 1000.00 mL of water at 10oC are poured into a glass cylinder, the height of the water column is 1000.00 mm. The w

Dafna11 [192]

Answer:

$\mathbf{h_2 =1021.9 \ mm}$

Explanation:

Given that :

The initial volume of water $V_1$ = 1000.00 mL = 1000000 mm³

The initial temperature of the water $T_1$ = 10° C

The height of the water column h = 1000.00 mm

The final temperature of the water $T_2$ = 70° C

The coefficient of thermal expansion for the glass is ∝ = $3.8*10^{-6 } mm/mm \ per ^oC$

The objective is to determine the the depth of the water column

In order to do that we will need to determine the volume of the water.

We obtain the data for physical properties of water at standard sea level atmospheric from pressure tables; So:

At temperature $T_1 = 10 ^ 0C$ the density of the water is $\rho = 999.7 \ kg/m^3$

At temperature $T_2 = 70^0 C$ the density of the water is $\rho = 977.8 \ kg/m^3$

The mass of the water is $\rho V = \rho _1 V_1 = \rho _2 V_2$

Thus; we can say $\rho _1 V_1 = \rho _2 V_2$ ;

⇒ $999.7 \ kg/m^3*1000 \ mL = 977.8 \ kg/m^3 *V_2$

$V_2 = \dfrac{999.7 \ kg/m^3*1000 \ mL}{977.8 \ kg/m^3 }$

$V_2 = 1022.40 \ mL$

$v_2 = 1022400 \ mm^3$

Thus, the volume of the water after heating to a required temperature of $70^0C$ is 1022400 mm³

However; taking an integral look at this process; the volume of the water before heating can be deduced by the relation:

$V_1 = A_1 *h_1$

The area of the water before heating is:

$A_1 = \dfrac{V_1}{h_1}$

$A_1 = \dfrac{1000000}{1000}$

$A_1 = 1000 \ mm^2$

The area of the heated water is :

$A_2 = A_1 (1 + \Delta t \alpha )^2$

$A_2 = A_1 (1 + (T_2-T_1) \alpha )^2$

$A_2 = 1000 (1 + (70-10) 3.8*10^{-6} )^2$

$A_2 = 1000.5 \ mm^2$

Finally, the depth of the heated hot water is:

$h_2 = \dfrac{V_2}{A_2}$

$h_2 = \dfrac{1022400}{1000.5}$

$\mathbf{h_2 =1021.9 \ mm}$

Hence the depth of the heated hot water is $\mathbf{h_2 =1021.9 \ mm}$

4 0

3 years ago