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sertanlavr [38]
3 years ago
11

What is the mass, in grams, of 1.15 mol of water, H2O?

Chemistry
1 answer:
garri49 [273]3 years ago
8 0
M = n x Mr

Mr of H20 - 18.006

M = 1.15mol x 18.006g/mol
= 20.7069g
= 20.7g (3sfg)
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An aqueous magnesium chloride solution is made by dissolving 7.15 moles of MgCl2 in sufficient water so that the final volume of
irinina [24]

Answer:

2.86mol/L

Explanation:

Given parameters:

Number of moles of MgCl₂  = 7.15moles

Volume of solution  = 2.50L

Unknown:

Molarity of the MgCl₂ solution = ?

Solution:

The molarity of a solution is the number of moles of solute found in a given volume.

  Molarity  = \frac{number of moles }{volume}  

 Insert the parameters and solve;

   Molarity  = \frac{7.15}{2.5}   = 2.86mol/L

4 0
3 years ago
Identify the reactants and the products of the preparation step to the urea cycle.
Salsk061 [2.6K]

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7 0
3 years ago
Describe the evidence of changes in organisms in the Cambrian Era that are reflected in the fossil record.​
UkoKoshka [18]

Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

Explanation:

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3 0
3 years ago
Find the pH of 8.4x10^-8 M HCl. Report the answer to the hundredths place.
Hunter-Best [27]

Answer:

pH = 7.08

Explanation:

HCl ---------> H^+ + Cl^-

It's an acid, we are using this formula

pH = -log [H]^+

H^+ = 8.4 * 10^-8

pH = - log [8.4 * 10^-8]

It can also be solved as

-log 8.4-(-8log 10)

-0.924-(-8×1)

-0.924+8

7.076

To the nearest hundredth

pH = 7.08

8 0
4 years ago
Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen
Darya [45]

Answer: The empirical formula of the compound becomes CH_2O

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol

\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol

\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

\text{Mole fraction of C}=\frac{3.023}{3.023}=1

\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2

\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes CH_2O

5 0
3 years ago
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